Time and Distance  For SBI PO Set – 7

1) If a person walks at 12 kmph he covers a certain distance. If he walks at 17 kmph, he covers 8.5 km more. How much distance did he actually cover?

a) 24 km

b) 4 km

c) 36 km

d) 6 km 

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   b) 4 km

Explanation

The difference between the speeds is 5 kmph.

So for 8.5 miles it takes 8.5/5 = 1.7 hrs

Therefore Actual distance = 12 x 1.7 = 20.4 km

2) A and B are moving in a circular track of 10 km in the same direction. Their speeds are 4 kmph and 5 kmph respectively. When will they meet each other if B starts at 8 am and A starts at 9:30 am from a same point?

a) 12 am

b) 10.30 am

c) 12 pm

d) 2.30 

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 c) 12 pm

 

Explanation

Relative Speed = 5 – 4 = 1 kmph

Relative distance = 2.5 km (Since B started and travelled 7.5 km in an hour, he is 2.5 km ahead of A)

Time taken = 2.5 hours

They will meet at 9.5 + 2.5 = 12 pm  

3) The speed of the stream is 5km/hr.A motorboat goes 10 km upstream and back again to the starting point in 50 minutes.what is the speed of the motorboat in still water?

a) 20km/hr

b) 25km/hr

c) 28km/hr

d) 30km/hr

e) None of these 

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 b) 25km/hr

 

Explanation

let the speed of the motorboat in still water be x km/hr

The speed of the motorboat along the stream=x+5 km/hr

The speed of the motorboat against the stream=x-5 km/hr

10/x+5 + 10/x-5=50/60

10(x-5+x+5)/(x+5)(x-5)=5/6

20x*6=5(x^2-25)

5(x^2-25)=5(24x)

x^2-25-24x=0

x^2-24x-25=0

now we take factorize

x=25 or -1

x=25 km/hr

4) In a flight of 600kms,an aircraft was slowed down due to bad wheather. its average speed for the trip is reduced by 200kms/hr. and the time of flight increased by 30 min. the duration of the flight is.

a) 1hr

b) 2hrs

c) 3hrs

d) 4hrs

e) 5hrs 

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 a) 1hr

 

Explanation

let the duration of flight be “t” hours

s=d/t

s1-s2=200kms/hr

600/t – 600/t+1/2=200

600/t – 2*600/2t+1=200

(2t+1)600-t*1200=200t(2t+1)

3(2t+1)-6t=t(2t+1)

6t+3-6t=2t^2+t

t(2t+3)-1(2t+3)=0

(2t+3)(t-1)=0

t=1 hour

 

5) A business man travelled 120km by bus ,Which formed 2/5 of his trip.He travelled 1/3 of the whole trip by car and the rest by train.The distance travelled by train is

a) 60km

b) 70km

c) 80km

d) 90km

e) None of these 

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Explanation

2/5 x = 120km

Total distance = x(5×120)/2 = 300km

Remaining trip = 300 – 120 = 180

Distance travelled by car = 300/3 = 100km

Distance travelled by train = 180 – 100 = 80km

6) Two trains are moving in opposite direction having speed in the ratio 5:7. First train crosses a pole in 12 second and second train crosses the same pole n 15 second. Find the time in which they can cross each other completely.

a) 55/4 sec

b) 53/4 sec

c) 57/4 sec

d) 59/4 sec

e) None of these 

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 a) 55/4 sec

 

Explanation :

Let the length of first train and second train be a and b meter. Then

a = 5x*12 = 60x and b = 7x*15 = 105x

They are moving in opposite direction, 165x = (12x)*T

T = 165/12 = 55/4 sec  

7) Two cars start together in the same direction from the same place. The first goes with uniform speed of 10 kmph. The second goes at a speed of 8 kmph in the first hour and increases its speed by 1/2 kmph each succeeding hours. After how many hours will the second car overtake the first, if both cars go non stop?

a) 8 hours

b) 7 hours

c) 6 hours

d) 9 hours

e) 5 hours 

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 d) 9 hours

Explanation :

The second car overtake the first car in x hours

Distance covered by the first car in x hours = Distance covered by the second car in x hours

10x = x/2[2a + (x-1)d] 10x = x/2[2*8 + (x-1)1/2] x = 40 -31 = 9  

8) A person covered some distance in 24 hours. He covered half the distance by rail @ 75 km per hour and the rest by car @ 45 km/hr. The total distance covered by him was

a) 900 km

b) 1350 km

c) 675 km

d) 2700 km

e) None of these 

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 b) 1350 km

Explanation

Lets the total distance be 2D. Now

D = 675

Total distance = 2 x D = 2 x 675

= 1350 km  

9)  A person covered some distance in 24 hours. He covered half the distance by rail @ 75 km per hour and the rest by car @ 45 km/hr. The total distance covered by him was

a) 900 km

b) 1350 km

c) 675 km

d) 2700 km

e) None of these 

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 b) 1350 km

 

Explanation

Lets the total distance be 2D. Now

D/75 + D/45 = 24

D = 675

Total distance = 2 x D = 2 x 675

= 1350 km  

10) A truck covers a distance of 256 km at the speed of 32 km/h. What is the average speed of a car which travels a distance of 160 km more than the truck in the same time?

a) 46 km/h

b) 52 km/h

c) 49 km/h

d) 64 kmh

e) None of these 

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 b) 52 km/h

 

Explanation

256/32 = 8 hours

256+160 = 416 km

416/8=52km/h