Crack IBPS PO : Quadratic Equation day 3
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IBPS PO Algebra 2
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IBPS PO Study Planner
IBPS PO Quadratic Equation – 2
No.of Questions: 10
Time : 10 mints
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Question 1 of 10
1. Question
1 pointsCategory: AptitudeIn the following questions, two equations numbered I and II are given. On solving them, we will get the value of X and Y in equation I and II respectively. Solve for both the equations and choose the correct option.
I. 4a^2=1
II.2b^2+5b+2=0
Correct
b
I. 4a^2=1
a=±0.5
a≥b
Incorrect
b
I. 4a^2=1
a=±0.5
a≥b

Question 2 of 10
2. Question
1 pointsCategory: AptitudeI .a^2+a=6
II.b^25b+6=0
Correct
Incorrect

Question 3 of 10
3. Question
1 pointsCategory: AptitudeI.6a^2+17a+10=0
II.2b^2+7b+6=0
Correct
Incorrect

Question 4 of 10
4. Question
1 pointsCategory: AptitudeI.3a^2=24a
II.b^2=64
Correct
c
I.3a^2=24a
a=0, 8
II.b^2=64
b=±8
relationship cannot be determined
Incorrect
c
I.3a^2=24a
a=0, 8
II.b^2=64
b=±8
relationship cannot be determined

Question 5 of 10
5. Question
1 pointsCategory: AptitudeI.11a^214a+3=0
II.b^214b+13=0
Correct
Incorrect

Question 6 of 10
6. Question
1 pointsCategory: Aptitude x^{2}+ 78x + 1520 = 0
 y^{2}+ 63y + 920 = 0
Correct
From I,
Therefore,
X =40, 38
From II,
Therefore
y = 40, 23
Hence, Relation cannot be determined between x and y.
Incorrect
From I,
Therefore,
X =40, 38
From II,
Therefore
y = 40, 23
Hence, Relation cannot be determined between x and y.

Question 7 of 10
7. Question
1 pointsCategory: Aptitude (19x+323) (29x+ 783) = 0
 ( 97y+ 1649) (49y1127)=0
Correct
d
From I,
X = 17, 27
From II,
Y = 17, +23
Hence, y ≥x
Incorrect
d
From I,
X = 17, 27
From II,
Y = 17, +23
Hence, y ≥x

Question 8 of 10
8. Question
1 pointsCategory: AptitudeI.46x^{2}+31x15 = 0
II. y^{2}+4y+3 = 0
Correct
c
From I,
Therefore, x = 46/46, 15/46 = 1 , 15/46.
From II,
Therefore, y = 1, 3
Hence, y ≤x
Incorrect
c
From I,
Therefore, x = 46/46, 15/46 = 1 , 15/46.
From II,
Therefore, y = 1, 3
Hence, y ≤x

Question 9 of 10
9. Question
1 pointsCategory: Aptitude 19x+ 48x+ 8x – 8^{2}x+ 12×11= 13^{2} – 4
 √(72y^2 )+ √(162y^2 ) = √1800
Correct
d
From I,
11x = 33
X= 3
From II,
15√2 y = 30√2
Y = 2
Hence, x> y
Incorrect
d
From I,
11x = 33
X= 3
From II,
15√2 y = 30√2
Y = 2
Hence, x> y

Question 10 of 10
10. Question
1 pointsCategory: Aptitude 17^{x} – 5^{2} 14= 43^{2} + 55^{2}
 27^{y} – 98^{2} = 101^{2}11^{2}1
Correct
e
From I,
17^{x} = 17^{3}
Therefore, x = 3
From II,
27^{y} = 27^{3}
Y = 3
Hence, x=y
Incorrect
e
From I,
17^{x} = 17^{3}
Therefore, x = 3
From II,
27^{y} = 27^{3}
Y = 3
Hence, x=y
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