SOLVE PROBLEMS BASED ON AGES-LEARN SERIES
Want to crack Bank, SSC & Govt Recruitment Exams?
Get Coaching in RACE Institute
Lowest Fee & 100% Result oriented Practice Strategy
SOLVE PROBLEMS BASED ON AGES-LEARN SERIES
Hi Bankersdaily Aspirants,
Aspirants,IBPS exams are going to be held shortly,Nowadays there is heavy competition for all the competitive exams that too for banking sector there is more competition,In order to increase our pass percentage,we are providing articles in each topic in all the section by initiating a new concept now as Learn Series.In Learn Series we are providing shortcuts for all the topics.click below,to read shortcuts on all the topics
Read Shortcut Methods for all the Topics-Learn Series
Introduction:
Today we are going to discuss on AGES this is quite easy when comparing other application sums and it take just few seconds to solve the question.
And it carries 1 or 2 marks in the Prelims as well as in Mains
There are only 3 Types of problems in ages namely:
1.Finding Present Age
2.Finding Previous Age(Age before some years)
3.Finding Future Age(Age after Some years)
TYPE 1:
BASED ON FINDING PRESENT AGE:
1.The ages of Rahul and Amit are in the Ratio of 9:6.Their sum of the ages be 95.Find the age of Rahul?
Rahul age=9X Amit Age=6X
Sum of their Ages be(9X+6X)=15X
Rahul’s age=95*(9/15)
=57 years
2.Present Ages of Sameer and Anand are in the ratio of 5:4 respectively.Three years hence,the ratio of their ages will become 11:9 respectively.What is Anand’s Present age in years?
Person |
Present Year |
After 3 Year |
Sameer | 5x | 5x+3=11 |
Anand | 4x | 4x+3=9 |
9(5X+3)=11(4X+3)
45X+27=44X+33
X=6
Anand’s Present Age=4*6=24Years
3.A father said to his son,”I was as old as you are at the present at the time of your birth”,If the father’s age is 38 years now,the son’s age is?
Let the son’s present age be X,
Then,(38-X)=X
2X=38
X=19 years
TYPE 2:
BASED ON EFFICIENCY:
1)A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of his son is?
Let Son’s Age=X
Man Age =24 + X
After two years:
24 + X+2=2(X+2)
26 + X=2x+4
X=22 years
2)A is two years older than B who is twice as old as C.If the total of the ages of A,B and C be 27,then how old is B?
A | B | C |
2X+2 | 2X | X |
(2X+2) +2X + X=27
5X+2=27 5X=25 X=5
B=2X, B=2*5
B=10years.
You may also like to read:
HOW TO SOLVE MIXTURE AND ALLIGATION PART 3-TIPS,TRICKS AND SHORTCUTS
HOW TO SOLVE MIXTURE AND ALLIGATION PART 2-TIPS,TRICKS AND SHORTCUTS
CAN YOU SOLVE INEQUALITIES IN LESS THAN 20 SEC : DIRECT INEQUALITIES PART 1