Crack IBPS PO : Missing Data Interpretation : Day 48
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Crack IBPS PO : Missing Data Interpretation : Day 48
Directions : 1-5) Refer to the following table and answer the questions.
Marks obtained by three students A, B and C in an entrance examination is provided in the table Given below:
| Sections | Paper I marks
MM (25) |
Paper II marks
MM (40) |
Paper III marks
MM (100) |
Maximum Marks
MM (130) |
||||||||
| A | B | C | A | B | C | A | B | C | A | B | C | |
| Reasoning | 22 | 17 | 10 | 36 | 36 | 30 | – | 95 | 80 | 116.8 | – | – |
| Verbal | 19 | 18 | 21 | 33 | – | 36 | 81 | 84 | 75 | – | 104.55 | – |
| Quant | 24 | – | 19 | 31 | 27 | 35 | 97 | 93 | 85 | – | 113.75 | – |
| Gk | 20 | 16 | 13 | 23 | 34 | 38 | 73 | 89 | 92 | – | – | – |
| Computer | – | 14 | 18 | 38 | 37 | 40 | 65 | – | 79 | 95.4 | 105.35 | – |
Normalised marks is given by: Normalised marks (130) = paper I (10) + paper II (30) + paper III(90)
Suppose a student gets 10 out of 25 in paper I, 40 out of 40 in paper II and 60 out of 100 in paper III , then normalised marks = 4 + 30 + 54 = 88 (out of 130).
Total Marks obtained in the examination= Total of the Normalised Marks of all the sections
Percentage marks = ((Total Marks obtained in the examination)/650)×100
Q.1) What is the total percentage scored by student C in the entrance examination?
a) 82.5%
b) 75.5%
c) 85.5%
d) 78%
e) None of these.
Q.2) Due to illness a student A was unable to give the Paper I of sections Verbal and Gk then what is the total percentage scored by him in the examination?
a) 72.37%
b) 76.57%
c) 78.92%
d) 78.57%
e) None of these
Q.3) What is the difference between the average marks per section obtained by student A and B in paper I?
a) 3.2
b) 4
c) 3.8
d) 3.6
e) 4.6
Q.4) What is the ratio of total marks in paper II scored by student A, B and C respectively?
a) 161 : 164 : 179
b) 161 : 163 : 178
c) 131 : 151 : 171
d) 131 : 161 : 179
e) 161 : 163 : 179
Q.5) What is the total normalized marks obtained by student A?
a) 511.25
b) 522.55
c) 516.55
d) 517.55
e) None of these
Directions : 6-10) Find the wrong number in the series.
Q.6) 90 132 132 181 182 240
a) 181
b) 182
c) 90
d) 240
e) 130
Q.7) 9 18 91 61 341
a) 341
b) 61
c) 91
d) 18
e) None of these
Q.8) 2 6 18 40 145 756
a) 756
b) 145
c) 2
d) 6
e) None of these
Q.9) 4 6 13.5 46.56 230.66
a) 6
b) 46.56
c) 230.66
d) 4
e) None of these
Q.10) 642 81 28 19 18
a) 642
b) 18
c) 81
d) 28
e) 19
3 comments
I couldn’t understand this missing data interpretation. Can you please share me the basic tricks involved in it?
Can any one explain how it is 650 in the 1st problem
Required percentage = 536.55/650×100=82.5%
For Each paper, 130 is the maximum mark. There are 5 Subjects so the total marks is 650.