## Crack IBPS PO : Missing Data Interpretation : Day 48

**Directions : 1-5) Refer to the following table and answer the questions.**

Marks obtained by three students A, B and C in an entrance examination is provided in the table Given below:

Sections | Paper I marks
MM (25) |
Paper II marks
MM (40) |
Paper III marks
MM (100) |
Maximum Marks
MM (130) |
||||||||

A | B | C | A | B | C | A | B | C | A | B | C | |

Reasoning | 22 | 17 | 10 | 36 | 36 | 30 | – | 95 | 80 | 116.8 | – | – |

Verbal | 19 | 18 | 21 | 33 | – | 36 | 81 | 84 | 75 | – | 104.55 | – |

Quant | 24 | – | 19 | 31 | 27 | 35 | 97 | 93 | 85 | – | 113.75 | – |

Gk | 20 | 16 | 13 | 23 | 34 | 38 | 73 | 89 | 92 | – | – | – |

Computer | – | 14 | 18 | 38 | 37 | 40 | 65 | – | 79 | 95.4 | 105.35 | – |

**Normalised marks is given by: Normalised marks (130) = paper I (10) + paper II (30) + paper III(90)**

Suppose a student gets 10 out of 25 in paper I, 40 out of 40 in paper II and 60 out of 100 in paper III , then normalised marks = 4 + 30 + 54 = 88 (out of 130).

Total Marks obtained in the examination= Total of the Normalised Marks of all the sections

Percentage marks = ((Total Marks obtained in the examination)/650)×100

Q.1) What is the total percentage scored by student C in the entrance examination?

a) 82.5%

b) 75.5%

c) 85.5%

d) 78%

e) None of these.

Q.2) Due to illness a student A was unable to give the Paper I of sections Verbal and Gk then what is the total percentage scored by him in the examination?

a) 72.37%

b) 76.57%

c) 78.92%

d) 78.57%

e) None of these

Q.3) What is the difference between the average marks per section obtained by student A and B in paper I?

a) 3.2

b) 4

c) 3.8

d) 3.6

e) 4.6

Q.4) What is the ratio of total marks in paper II scored by student A, B and C respectively?

a) 161 : 164 : 179

b) 161 : 163 : 178

c) 131 : 151 : 171

d) 131 : 161 : 179

e) 161 : 163 : 179

Q.5) What is the total normalized marks obtained by student A?

a) 511.25

b) 522.55

c) 516.55

d) 517.55

e) None of these

**Directions : 6-10) Find the wrong number in the series.**

Q.6) 90 132 132 181 182 240

a) 181

b) 182

c) 90

d) 240

e) 130

Q.7) 9 18 91 61 341

a) 341

b) 61

c) 91

d) 18

e) None of these

Q.8) 2 6 18 40 145 756

a) 756

b) 145

c) 2

d) 6

e) None of these

Q.9) 4 6 13.5 46.56 230.66

a) 6

b) 46.56

c) 230.66

d) 4

e) None of these

Q.10) 642 81 28 19 18

a) 642

b) 18

c) 81

d) 28

e) 19

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## 3 comments

I couldn’t understand this missing data interpretation. Can you please share me the basic tricks involved in it?

Can any one explain how it is 650 in the 1st problem

Required percentage = 536.55/650×100=82.5%

For Each paper, 130 is the maximum mark. There are 5 Subjects so the total marks is 650.

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