Crack IBPS PO : Aptitude Miscellaneous Day 13
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IBPS PO Study Planner
Miscellaneous Day 13
No.of Questions: 10
Time : 10 minutes
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Question 1 of 10
1. Question
1 points
Category: Aptitude
A car covers a distance of 420 km in a certain time at a speed of 60 km/hr. How much distance would a truck cover at an average speed which is 20km/hr less than that of the speed of the car in time which is 5 hours more than that time taken by the car?





Correct
(a)
Time taken by car=420/60=7 hrs
Time taken by truck=5+7=12 hrs
speed of the truck=6020=40km/hr
∴ Required distance=40×12=480 km
Incorrect
(a)
Time taken by car=420/60=7 hrs
Time taken by truck=5+7=12 hrs
speed of the truck=6020=40km/hr
∴ Required distance=40×12=480 km

Question 2 of 10
2. Question
1 points
Category: Aptitude
The two friends vijay and senthil has some amount of money.If Vijay gives Rs.50 to senthil, and then senthil have money which is equal to vijay which he had now. If senthil gives Rs.40 to Vijay, then Vijay will have four times as much as money left with Senthil. How much money does each have? (In Rs.)





Correct
(a)
Suppose Vijay has Rs. x and Senthil has Rs. Y,
Then 1^{st} condition,
x50=y+50
xy=100 →1
2^{nd} condition,
4(y40)=x+40
x4y=200 →2
Solve 1 and 2 we get x=200, y=100
∴ Vijay has Rs.200 and Senthil has Rs.100
Incorrect
(a)
Suppose Vijay has Rs. x and Senthil has Rs. Y,
Then 1^{st} condition,
x50=y+50
xy=100 →1
2^{nd} condition,
4(y40)=x+40
x4y=200 →2
Solve 1 and 2 we get x=200, y=100
∴ Vijay has Rs.200 and Senthil has Rs.100

Question 3 of 10
3. Question
1 points
Category: Aptitude
In a village, 20% of the villagers belongs from upper economic class. The number of villagers who belongs from middle economic class is fourfifth of the number of villagers who belongs from lower economic class. If the number of villagers graduated from lower economic is 1850, which is 50% of the total number of villagers from lower economic class, what is the total population in that village?





Correct
(a)
Total number of villagers from lower economic class =1850× 100/50=3700
Total number of villagers from middle economic class = 4/5×3700=2960
Total population of village =(3700+2960)×100/80=8325
Incorrect
(a)
Total number of villagers from lower economic class =1850× 100/50=3700
Total number of villagers from middle economic class = 4/5×3700=2960
Total population of village =(3700+2960)×100/80=8325

Question 4 of 10
4. Question
1 points
Category: Aptitude
A water tank has one inlet pipe P and one outlet pipe Q. P takes 6 hours to fill the empty tank and Q takes 10 hours to empty the full tank, if the tank is three fifth full, how much time will it take to fill the tank completely when both pipes P and Q are opened simultaneously? (in hours)





Correct
(b)
P and Q can fill the tank in 1hour,
=1/61/10=4/60=1/15 hrs
Remaining work =1 3/5=2/5 th
∴ Required time =15 × 2/5=6 hours
Incorrect
(b)
P and Q can fill the tank in 1hour,
=1/61/10=4/60=1/15 hrs
Remaining work =1 3/5=2/5 th
∴ Required time =15 × 2/5=6 hours

Question 5 of 10
5. Question
1 points
Category: Aptitude
If 1 is added to the denominator of a fraction so the fraction becomes ¾.Then If 1 is added to the numerator of a fraction so the fraction becomes 1, then find the product of the squares of the numerator and denominator of the fraction,





Correct
(c)
Let Numerator of the fraction is x and the denominator of the fraction is y
1^{st} condition,
x/(y+1)=3/4 =>4x3y=3 →1
2^{nd} condition,
(x+1)/y=1 =>xy=1 →2
Solve the equation 1 and 2 we get,
X=6, y=7
Required product =6^2×7^2=1764
Incorrect
(c)
Let Numerator of the fraction is x and the denominator of the fraction is y
1^{st} condition,
x/(y+1)=3/4 =>4x3y=3 →1
2^{nd} condition,
(x+1)/y=1 =>xy=1 →2
Solve the equation 1 and 2 we get,
X=6, y=7
Required product =6^2×7^2=1764

Question 6 of 10
6. Question
1 points
Category: Aptitude
The sum of the ages of four members of a family 6 years ago was 86 years. Today, when the daughter has been married off and she replaced by a daughterinlaw, now the sum of the total family members ages is 90. Assuming that there has been no other changes in the family structure all the people are alive, what is the difference between the ages of the daughter and the daughterinlaw?





Correct
(b)
Sum of the present ages of old family =86+(6×4)=110
Father+ Mother + Son + daughterinlaw =90 years
Required difference =11090=20 years
Incorrect
(b)
Sum of the present ages of old family =86+(6×4)=110
Father+ Mother + Son + daughterinlaw =90 years
Required difference =11090=20 years

Question 7 of 10
7. Question
1 points
Category: Aptitude
A sum of Rs.5000 is divided into two parts such that one part is invested at 15% p.a. simple interest and the second part at 20% p.a. compound interest, after two years, the interest received is Rs.2032 , then the ratio of investment of first to second part is,





Correct
(c)
1^{st} part =x, 2^{nd} part =5000x
According to the question,
PNR/100+P( (1+R/100)^n1)=2032
x×2×15/100+(5000x)((1+20/100)^21)=2032
Solve the equation, we get x=1200
Required ratio =1200 :3800=6:19
Incorrect
(c)
1^{st} part =x, 2^{nd} part =5000x
According to the question,
PNR/100+P( (1+R/100)^n1)=2032
x×2×15/100+(5000x)((1+20/100)^21)=2032
Solve the equation, we get x=1200
Required ratio =1200 :3800=6:19

Question 8 of 10
8. Question
1 points
Category: Aptitude
In a cricket team the average age of eleven players is 30 years. Out of these, each group consist of three players and the average age of three groups are 28years,30years and 32years respectively. In these groups,the ages of captain and the youngest player are not included, and the captain is fourteen years older than the youngest player, what is the age of the captain?





Correct
(d)
Sum of the ages of eleven players =30×11=330
According to the question,
30×11=(28×3+30×3+32×3+captain+youngest player)
Captain+youngest player=330270=60 →1
Captainyoungest player=14 →2
Solve 1 and 2 we get, captain= 37 years
Incorrect
(d)
Sum of the ages of eleven players =30×11=330
According to the question,
30×11=(28×3+30×3+32×3+captain+youngest player)
Captain+youngest player=330270=60 →1
Captainyoungest player=14 →2
Solve 1 and 2 we get, captain= 37 years

Question 9 of 10
9. Question
1 points
Category: Aptitude
Shivani’s monthly income is equal to two by fifth of the cost of 16 kg of strawberry. Cost of 8 kg of strawberry is equal to the 24 kg of grapes. If the cost of 10 kg of grapes is Rs. 1800, what is the annual income of Shivani?





Correct
(e)
Cost per kg of grapes = 1800/10=Rs.180
Cost of 24 Kg gapes =24×180=Rs.4320=8 Kg of strawberry
Cost of 16 Kg Strawberry = 4320/8×16=8640
Shivani’s monthly income = 2/5×8640=1728×2=Rs.3456
Shivani’s annual income =12×3456=Rs.41472
Incorrect
(e)
Cost per kg of grapes = 1800/10=Rs.180
Cost of 24 Kg gapes =24×180=Rs.4320=8 Kg of strawberry
Cost of 16 Kg Strawberry = 4320/8×16=8640
Shivani’s monthly income = 2/5×8640=1728×2=Rs.3456
Shivani’s annual income =12×3456=Rs.41472

Question 10 of 10
10. Question
1 points
Category: Aptitude
Shiva purchases a washing machine with a marked price of Rs. 8000 but during sale,the discount of 20% was offered on the marked price.After that he further got a discount of 10% on the amount arrived , after giving 20% discount. What was the final amount paid by Shiva?





Correct
(a)
Selling price of the washing machine =8000 20/100×8000=6400
Final amount paid by shiva =6400 10/100×6400=Rs.5760
Incorrect
(a)
Selling price of the washing machine =8000 20/100×8000=6400
Final amount paid by shiva =6400 10/100×6400=Rs.5760
Quizsummary
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Information
IBPS PO Study Planner
Miscellaneous Day 13
No.of Questions: 10
Time : 10 minutes
All the Best!!!
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Categories
 Aptitude 0%
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 Answered
 Review

Question 1 of 10
1. Question
1 pointsCategory: AptitudeA car covers a distance of 420 km in a certain time at a speed of 60 km/hr. How much distance would a truck cover at an average speed which is 20km/hr less than that of the speed of the car in time which is 5 hours more than that time taken by the car?
Correct
(a)
Time taken by car=420/60=7 hrs
Time taken by truck=5+7=12 hrs
speed of the truck=6020=40km/hr
∴ Required distance=40×12=480 km
Incorrect
(a)
Time taken by car=420/60=7 hrs
Time taken by truck=5+7=12 hrs
speed of the truck=6020=40km/hr
∴ Required distance=40×12=480 km

Question 2 of 10
2. Question
1 pointsCategory: AptitudeThe two friends vijay and senthil has some amount of money.If Vijay gives Rs.50 to senthil, and then senthil have money which is equal to vijay which he had now. If senthil gives Rs.40 to Vijay, then Vijay will have four times as much as money left with Senthil. How much money does each have? (In Rs.)
Correct
(a)
Suppose Vijay has Rs. x and Senthil has Rs. Y,
Then 1^{st} condition,
x50=y+50
xy=100 →1
2^{nd} condition,
4(y40)=x+40
x4y=200 →2
Solve 1 and 2 we get x=200, y=100
∴ Vijay has Rs.200 and Senthil has Rs.100
Incorrect
(a)
Suppose Vijay has Rs. x and Senthil has Rs. Y,
Then 1^{st} condition,
x50=y+50
xy=100 →1
2^{nd} condition,
4(y40)=x+40
x4y=200 →2
Solve 1 and 2 we get x=200, y=100
∴ Vijay has Rs.200 and Senthil has Rs.100

Question 3 of 10
3. Question
1 pointsCategory: AptitudeIn a village, 20% of the villagers belongs from upper economic class. The number of villagers who belongs from middle economic class is fourfifth of the number of villagers who belongs from lower economic class. If the number of villagers graduated from lower economic is 1850, which is 50% of the total number of villagers from lower economic class, what is the total population in that village?
Correct
(a)
Total number of villagers from lower economic class =1850× 100/50=3700
Total number of villagers from middle economic class = 4/5×3700=2960
Total population of village =(3700+2960)×100/80=8325
Incorrect
(a)
Total number of villagers from lower economic class =1850× 100/50=3700
Total number of villagers from middle economic class = 4/5×3700=2960
Total population of village =(3700+2960)×100/80=8325

Question 4 of 10
4. Question
1 pointsCategory: AptitudeA water tank has one inlet pipe P and one outlet pipe Q. P takes 6 hours to fill the empty tank and Q takes 10 hours to empty the full tank, if the tank is three fifth full, how much time will it take to fill the tank completely when both pipes P and Q are opened simultaneously? (in hours)
Correct
(b)
P and Q can fill the tank in 1hour,
=1/61/10=4/60=1/15 hrs
Remaining work =1 3/5=2/5 th
∴ Required time =15 × 2/5=6 hours
Incorrect
(b)
P and Q can fill the tank in 1hour,
=1/61/10=4/60=1/15 hrs
Remaining work =1 3/5=2/5 th
∴ Required time =15 × 2/5=6 hours

Question 5 of 10
5. Question
1 pointsCategory: AptitudeIf 1 is added to the denominator of a fraction so the fraction becomes ¾.Then If 1 is added to the numerator of a fraction so the fraction becomes 1, then find the product of the squares of the numerator and denominator of the fraction,
Correct
(c)
Let Numerator of the fraction is x and the denominator of the fraction is y
1^{st} condition,
x/(y+1)=3/4 =>4x3y=3 →1
2^{nd} condition,
(x+1)/y=1 =>xy=1 →2
Solve the equation 1 and 2 we get,
X=6, y=7
Required product =6^2×7^2=1764
Incorrect
(c)
Let Numerator of the fraction is x and the denominator of the fraction is y
1^{st} condition,
x/(y+1)=3/4 =>4x3y=3 →1
2^{nd} condition,
(x+1)/y=1 =>xy=1 →2
Solve the equation 1 and 2 we get,
X=6, y=7
Required product =6^2×7^2=1764

Question 6 of 10
6. Question
1 pointsCategory: AptitudeThe sum of the ages of four members of a family 6 years ago was 86 years. Today, when the daughter has been married off and she replaced by a daughterinlaw, now the sum of the total family members ages is 90. Assuming that there has been no other changes in the family structure all the people are alive, what is the difference between the ages of the daughter and the daughterinlaw?
Correct
(b)
Sum of the present ages of old family =86+(6×4)=110
Father+ Mother + Son + daughterinlaw =90 years
Required difference =11090=20 years
Incorrect
(b)
Sum of the present ages of old family =86+(6×4)=110
Father+ Mother + Son + daughterinlaw =90 years
Required difference =11090=20 years

Question 7 of 10
7. Question
1 pointsCategory: AptitudeA sum of Rs.5000 is divided into two parts such that one part is invested at 15% p.a. simple interest and the second part at 20% p.a. compound interest, after two years, the interest received is Rs.2032 , then the ratio of investment of first to second part is,
Correct
(c)
1^{st} part =x, 2^{nd} part =5000x
According to the question,
PNR/100+P( (1+R/100)^n1)=2032
x×2×15/100+(5000x)((1+20/100)^21)=2032
Solve the equation, we get x=1200
Required ratio =1200 :3800=6:19
Incorrect
(c)
1^{st} part =x, 2^{nd} part =5000x
According to the question,
PNR/100+P( (1+R/100)^n1)=2032
x×2×15/100+(5000x)((1+20/100)^21)=2032
Solve the equation, we get x=1200
Required ratio =1200 :3800=6:19

Question 8 of 10
8. Question
1 pointsCategory: AptitudeIn a cricket team the average age of eleven players is 30 years. Out of these, each group consist of three players and the average age of three groups are 28years,30years and 32years respectively. In these groups,the ages of captain and the youngest player are not included, and the captain is fourteen years older than the youngest player, what is the age of the captain?
Correct
(d)
Sum of the ages of eleven players =30×11=330
According to the question,
30×11=(28×3+30×3+32×3+captain+youngest player)
Captain+youngest player=330270=60 →1
Captainyoungest player=14 →2
Solve 1 and 2 we get, captain= 37 years
Incorrect
(d)
Sum of the ages of eleven players =30×11=330
According to the question,
30×11=(28×3+30×3+32×3+captain+youngest player)
Captain+youngest player=330270=60 →1
Captainyoungest player=14 →2
Solve 1 and 2 we get, captain= 37 years

Question 9 of 10
9. Question
1 pointsCategory: AptitudeShivani’s monthly income is equal to two by fifth of the cost of 16 kg of strawberry. Cost of 8 kg of strawberry is equal to the 24 kg of grapes. If the cost of 10 kg of grapes is Rs. 1800, what is the annual income of Shivani?
Correct
(e)
Cost per kg of grapes = 1800/10=Rs.180
Cost of 24 Kg gapes =24×180=Rs.4320=8 Kg of strawberry
Cost of 16 Kg Strawberry = 4320/8×16=8640
Shivani’s monthly income = 2/5×8640=1728×2=Rs.3456
Shivani’s annual income =12×3456=Rs.41472
Incorrect
(e)
Cost per kg of grapes = 1800/10=Rs.180
Cost of 24 Kg gapes =24×180=Rs.4320=8 Kg of strawberry
Cost of 16 Kg Strawberry = 4320/8×16=8640
Shivani’s monthly income = 2/5×8640=1728×2=Rs.3456
Shivani’s annual income =12×3456=Rs.41472

Question 10 of 10
10. Question
1 pointsCategory: AptitudeShiva purchases a washing machine with a marked price of Rs. 8000 but during sale,the discount of 20% was offered on the marked price.After that he further got a discount of 10% on the amount arrived , after giving 20% discount. What was the final amount paid by Shiva?
Correct
(a)
Selling price of the washing machine =8000 20/100×8000=6400
Final amount paid by shiva =6400 10/100×6400=Rs.5760
Incorrect
(a)
Selling price of the washing machine =8000 20/100×8000=6400
Final amount paid by shiva =6400 10/100×6400=Rs.5760
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