Data Interpretation For SBI PO : Set – 42

D.1-5) Study the following table to answer the given questions.

Students English

(out of 180)

Science

(Out of 120)

GK

(Out of 100)

Maths

(Out of 200)

History

(Out of 75

Arjun 76% 80% 96% 59% 76%
Harini 83% 87% 90% 78% 80%
Ilakia 90% 91% 90% 85% 78%
Prem 54% 65% 80% 60% 50%
Sundar 67% 57% 75% 61% 45%

 

1) Find the total marks obtained by Prem all the subjects together ?

a) 345

b) 413

c) 456

d) 510

e) None of these

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b) 413

E = 54*180/100 =97

S = 65*120/100 =78

GK = 80*100/100 =80

M = 60*200/100 =120

H = 50*75/100 =38

Total = 97+78+80+120+38 = 413

2) What is the average marks obtained by all the students in GK ?

a) 65

b) 90

c) 86

d) 76

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C) 86

A = 96*10/100 =96

H = 90*100/100 =90

I =  90*100/100 =90

P = 80*100/100 =80

S = 75*100/100 =75

Avg = (96+90+90+80+75)/5 = 431/5 = 86.2 = 86

3) The marks scored by Sundar in History is approximately what % of the marks scored by him in English ?

a) 45%

b) 25%

c) 34%

d) 28%

e) None of these

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d) 28%

% = [(45*75/100)/ (67*180/100)]*100

= 34*100/121

%  = 28%

4) What is the overall % of marks obtained by Harini ?

a) 92.45%

b) 82.81%

c) 89.76%

d) 78.50%

e) None of these

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b) 82.81%

Total mark = (83*180/100)+(87*120/100)+(90*100/100)+(78*200/100)+(80*75/100)

Total mark    = 149+104+90+156+60 = 559

% = (559*100)/675 = 82.81%

5) Find the difference between the total marks obtained by Harini and Prem ?

a) 146

b) 150

c) 135

d)143

e) None of these

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a)

Harini = 559

Prem = 413

Diff = 559 – 413 = 146

 

D.6-10) Sales of mobile phone in the year 2005 and 2006 by the six branches A, B, C, D, E and F. Study the graph and answer the following questions.

 

6) Find the ratio of total sales of B in both years to the total sales of branch D in both years.

a) 9:7

b) 7:9

c) 5:3

d) 3:5

e) None of these

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b)

B = 75+65 = 140

D =85+95 = 180

B:D = 140:180 = 7:9

7) What is the average number of mobile phones sold in 2005 ?

a)60

b)65

c)70

d)80

e) None of these

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d)

Average = (80+75+95+85+75+70)/6 = 80

8) Which branch sold the maximum number of mobile phones in both years ?

a) A

b) B

c) C

d) Cannot be determined

e) None of these

e) None of these

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c)

A = 80 + 105 = 185

B = 75 + 65 = 140

C = 95 + 110 =205

D = 85 + 95 =180

E = 75 + 95 =170

F = 70 + 80 =150

9) What is the difference between the number of mobile phones sold in 2005  by branch A and 2006 by branch D ?

a) 5

b) 10

c) 15

d) 20

e) 15

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2005, A = 80

2006, D = 95

Diff = 95 – 80 = 15

10) Number of mobile phones sold by branch C is what percentage of the Total Number of mobile phones sold in 2006 ?

a) 10%

b) 20%

c) 25%

d) 30%

e) None of these

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b) 20%

2006, C = 110

2006 Total = 105+65+110+95+95+80 = 550

% = (110/550)×100 = 20%