Questions asked in IBPS PO Prelims 2017 Slot 1 – Number Series
Questions asked in IBPS PO Prelims 2017 Slot 1 – Number Series
1) 17, 98, 26,89,35, (80)
(17 + 9 =26, 26 + 9 =35, 98-9 =89, 89-9 =80)
2) 2,17,89,359,1079, 2159
(2*6+5 , 17*5+4, 89*4+3, 359*3+2, 1079*2+1)
3) 3,5,15,45,113, 243
(13+1, 23+2,33+3,43+4,53+5)
4) 7,4.5,5.5,12,49,393
(7*0.5+1, 4.5*1+1, 5.5*2+1, 12*4+1, 49*8+1)
5) 3240, 540, 108,27,9,4.5
(3240/6, 540/5, 108/4, 27/3,9/2)
All Questions asked in IBPS PO Prelims Slot 1
11 comments
got it ! it is correct.
How come :
3) 3,5,15,45,113, 243 ???? wrong explanation !!
How to solve 3rd? Anyone please answer
First find the differences dn apply d logic mentioned here…
+(5^3 +5) = +130, so next term is 113 + 130 = 243
explanation is correct. 1^3+1=2 so 3 + 2 gives 5, same way do for 113.
That was correct explanation only…
The logic is not for the given digits….
First find out the diff btwn two no.s…then you will understand that (1cube+1)=2
(2cube+1)=10
(3cube+3)=30
(4cube+4)=68
(5cube+5)=130.
Add 130 to 113 in given digits
Actually the logic they explained was for the difference btwn two no.s….
3,5,15,45,113,?
5-3=2=1^3+1,
15-5=10=2^3+2,
45-15=30=3^3+3,
113-45=68=4^3+4,
5^3+5=130
113+130=243
3+1^3+1,5+2^3+2,15+3^3+3,45+4^3+4,113+5^3+5…..
no 5-3=2=1que+1
15-5=10=2que+2
See the difference.. and their pattern
2 10 30 68 130