TARGET SBI EXAM 2018: DATA INTERPRETATION
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TARGET SBI EXAM 2018: DATA INTERPRETATION
Dear Bankersdaily Aspirants,
Hope , Your preparation for SBI Clerk & PO exam 2018 is good . Since SBI Clerk & PO exam is a Two level which will be conducted in an online mode, Competition will be higher for this SBI Clerk & PO Exam and the most important thing , Current affairs section will be there in this exam. So aspirants have to concentrate in Four sections namely Aptitude, Reasoning, English, Current Affairs.
The person with high speed and very good accuracy only can crack this exam to taste the success. The candidates will be selected on the basis of performance in this online exam test. So the candidate with consistent hard work and regular practice will crack the exam very easily.
Here are some questions which will help you to identify your level of preparation.
Exam: SBI Clerk & PO Exam 2018
Topic: Data Interpretation
Day: 27
Timing: 7 minutes
D.1-10) Refer to the following table and answer the questions.
(Assume cost price be Rs.100)
Item | profit | loss | Discount | Marked price
(in Rs.) |
A | 40% | – | 30% | – |
B | 12% | 140 | ||
C | 10% | 25% | – | |
D | 12.5% | 200 | ||
E | 17.5% | 120 |
1) what is the ratio between the marked price of item A and the marked price of item C?
a) 7 : 3
b) 4 : 5
c) 6 : 3
d) 4: 7
e) None of these
2) Item D’s discount rate is what percentage of item B’s discount rate?
a) 19.875%
b) 22.875%
c) 27.875%
d) 21.875
e) None of these
3) What is the discount rate of item E?
a) 41.25%
b) 31.25%
c) 27.08%
d) 22.75%
e) 30.75%
4) What is the difference between total marked price of item A, B, C, D, E and the total selling price of item A, B, C, D , and E?
a) Rs.240
b) Rs.248
c) Rs.228
d) Rs.250
e) None of these
5) If Item A’s profit % is decreased by 20% and Item C’s loss % is increased by 20% then what is the approximate different between the marked price of Item A and C?
a) Rs. 63
b) Rs.73
c) Rs.65
d) Rs.60
e) None of these.
6) Rahul invested 20% more than Mohit. Mohit invested 10% less than Ragu. If the total sum of their investment is Rs.17880, how much amount did Raghu invest?
a) Rs.6000
b) Rs.7000
c) Rs.8000
d) Rs.5000
e) cannot be determined.
7) A, B, C and D are four salesman in the first month they received a commission of Rs.3200 from their company and divided it in the ratio of 2 : 3 : 4 : 7 in the second month the commission doubled, the amount was doubled in the ratio 3 : 4 : 5 : 4. In the third month the commission tripled when compared to the first month and they shared in the ratio of 4 : 7 : 3: 2 and in the fourth month the commission became half of the previous month and they shared it in the ratio of 4 : 3 : 5 : 4 . What was the average monthly earning of C over the period?
a) 1575
b) 1675
c) 1625
d) 1525
e) None of these
8) How many 6 digit numbers can be formed out of the number 542658, which are even?
a) 480
b) 720
c) 360
d) 5040
e) None of these
9) Two shops A and B marked the same brand of jeans for Rs.900. Shop A offers successive discounts of 15% and 15% While shop B offers successive discounts of 20% and 10%. Then the difference in the selling price of jeans is?
a) Rs.2.25
b) Rs.3.35
c) Rs.4.45
d) Rs.5.55
e) None of these
10) Let us assume that 20g of sugar dissolves in 100g of water. Even an extra pellet will remain undissolved and sediment at the bottom of the solution. Now, water starts evaporating from 1kg of 7% solution at the rate of 32.5g per hour. After how long will the sediments start to evaporate?
a) 25 hours
b) 20 hours
c) 15 hours
d) 30 hours
e) None of these.
Answer key with Explanation
1) (e) Let A’s cost price be Rs.100
Profit% = Rs.40%
So, selling price = Rs.140
Discount% = 30%
Marked price = 70% of X=140
=Rs.200
Let C’s cost price be Rs.100
Loss% = Rs.10%
So, selling price = Rs.90
Discount % = 25%
Marked price = 75% of X=90
=Rs.120
Required Ratio = 200 : 120 = 5 : 3
2) (e) Let Item D’s cost price be Rs.100
Profit % = Rs.12.5
So, selling price = Rs.112.5
Marked price = Rs.200
“Discount rate =” ” 200-112.5″ /200 “×100= 43.75%”
Let Item B’s cost price be Rs.100
Profit % = Rs.12
So, selling price = Rs.112
Marked price = Rs.140
“Discount rate =” ” 140-112″ /140 “×100= 20%”
“Required percentage = ” 43.75/20 “×100 = 218.75%”
3) (c) So, selling price = Rs.82.5
Marked price = Rs.120
“Discount rate =” ” 120-82.5″ /120 “×100= 31.25%”
4) (e) Item B’s marked price =Rs.140
Item D’s marked price =Rs.200
Item E’s marked price =Rs.120
Let A’s cost price be Rs.100
Profit% = Rs.40%
So, selling price = Rs.140
Discount% = 30%
Marked price = 70% of X=140
=Rs.200
Let C’s cost price be Rs.100
Loss% = Rs.10%
So, selling price = Rs.90
Discount % = 25%
Marked price = 75% of X=90
=Rs.120
Let’s cost price be Rs.100
Item A’s Profit % = 40%
So, Item A’s selling price = Rs.140
Similarly,
Item B’s selling price = Rs.112
Item D’s selling price = Rs.112.5
Item C’s loss % = 10%
So, Item C’s selling price = Rs.90
Similarly,
Item D’s selling price = Rs.82.5
Difference = (140+200+120+200+120 )- (140+112+112.5+90+87.5)= Rs.238
5) (a) Let A’s cost price be Rs.100
Now A’s
Profit% = 20%
So, selling price = Rs.120
Discount% = 30%
Marked price = 70% of X=120
=Rs.170(approximately)
Let C’s cost price be Rs.100
Now C’s
Loss% = Rs.20
So, selling price = Rs.80
Discount % = 25%
Marked price = 75% of X= 80
=Rs.107( approximately)
Difference = 170-107= Rs.63
7) (a) Let the investment made by Raghu be 100x, so Mohit’s investment = 90x and rahul’s investment =108x
108x+90x + 100x = 298x = 17880
X=60
So, Raghu investment = 100x = Rs.6000.
8) (d) Total commission in first month = Rs.3200
Total commission in second month = Rs.6400
Total commission in thired month = Rs. 9600
Total commission in fourth month = Rs.4800
“C’s share in the commission =” 4/16 of 3200+ 5/16 of 6400+ 3/16 of 9600+ 5/16 “of 4800”
=800 + 2000 + 1800 + 1500 = Rs.6100
“C’s average monthly earnings = ” “6100” /4 “= Rs.1525.”
9) (a) Final selling price of jeans in shop A = (900- 900×0.15)- (900-900×0.15)×0.15 = Rs. 650.25
Final selling price of jeans in shop B = (900-900×0.20)- (900-900×0.20)×0.10= Rs.648
Difference = Rs.2.25
10) (b) Sedimentation occurs when more than 20g of sugar is present in 100g of water.
Amount of sugar in 1kg of water = 70g
“Amount of water needed for sedimentation to start = ” “70x×100″ /20 ” = 350g”
Amount of water that should evaporate = 1000-350 = 650g
“Time required for eveporation =” ” 650″ /”32.5 ” “= 20 hours.”
Day 27 | Puzzles-2 | Data Interpretation | Reading comprehension (new) |
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