## Time and Distance For SBI PO Set – 5

1)  A tap drops at a rate of one drop/second. 600 drops  make  100ml.  The  number  of  litres wasted  in  300  days  is  ?

a) 4320000

b) 43200

c) 432000

d) 4320

d) 4320

Explanation

300 days = 300 X 24 X 60 X 60 seconds

= 25920000 seconds

Total drops wasted = 25920000

600 drops = 100 ml

6 drops = 1 ml

25920000 drops = 1X25920000/6 = 4320000 m

2)  In a 400 m race, A beats B by 70 m or 7 seconds. A’s time over the course is

a) 40 sec

b) 47 sec

c) 33 sec

d) None of these

c) 33 sec

Explanation

yana & gupta travel for same amount of time and meet between x and y. distance is same as the ratio of their speed  time taken by both them is x hourse before they meet.

Yana take x+4 hourse

gupta take x+9 hourse

ratio of time =x+4:x+9

ratio of speed=x+9:x+4

yana travelled 48*x kms. Thios is the distance that gupta takes 9 hours to lover.

Gupta speed=48x/9 km/hr.

Ratio of yana and gupta speed are 1:(x+4)/(x+9)

48:48x/9::1:x+4/x+9

x/9=x+4/x+9

=x square +9x=9x+36

x=6

speed of gupta=48/x=48*6/9

=32kmph

3) A boy travels 600 kms to his house partly by train and partly by car. He takes 8 hours if he travels 120 kms by train and the rest by car. He takes 20 minutes more if he travels 200 km by train and rest by car. Find the speeds of the train and the car.

a) 60 km/hr and 80 km/hr

b) 60 km/hr and 70 km/hr

c) 80 km/hr and 70 km/hr

d) 80 km/hr and 60 km/hr

a) 60 km/hr and 80 km/hr

Let x= speed of train

Let y=speed of car

Travel time=distance/speed

+=8

+=8+=

Let u =, v =,

120u+480v=8à1

200u+400v=à2

1à600u+2400v=40

2à600u+1200v=25

1200v=15

V=

Y==

120u=8-480=8()=8-6=2

U==

X==60

Speed of train =60km/hr

Speed of car =80km/hr

4) Yana and Gupta leave points x and y towards y and x respectively simultaneously and travel in the same route. After meeting each other on the way, Yana takes 4 hours to reach her destination, while Gupta takes 9 hours to reach his destination. If the speed of Yana is 48 km/hr, what is the speed of Gupta?

a) 72 km/hr.

b) 39 km/hr

c) 32 km/hr.

d) 96 km/hr

c) 32 km/hr.

Explanation

yana & gupta travel for same amount of time and meet between x and y. distance is same as the ratio of their speed  time taken by both them is x hourse before they meet.

Yana take x+4 hourse

gupta take x+9 hourse

ratio of time =x+4:x+9

ratio of speed=x+9:x+4

yana travelled 48*x kms. Thios is the distance that gupta takes 9 hours to lover.

Gupta speed=48x/9 km/hr.

Ratio of yana and gupta speed are 1:(x+4)/(x+9)

48:48x/9::1:x+4/x+9

x/9=x+4/x+9

=x square +9x=9x+36

x=6

speed of gupta=48/x=48*6/9

=32kmph

5)  In a 500 m race the ratio of speeds of A and B Is 3:4. A has a start of 140m. Then A wins by

a) 60

b) 20

c) 50

d) 10

b) 20

Explanation

to reach the winning post A will have to cover a distance of (500-140)mI.e 360m

while A cover 3 m, b covers(4/3*360)m=480m A reaches the winning post,B covers 480m and therfore 20m behind. Therfore wins by 20m.

6) A and B take part in 100 m race, A runs  at 18 kmph. A gives B a start of 4 m and still beats him by 4 seconds. The speed of B is

a) 15 kmph

b) 4 kmph

c) 4 kmph

d) 4 kmph

b) 4 kmph

7)  If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:

a) 50 km

b) 56 km

c) 70 km

d) 80 km

a) 50 km

Explanation

Let the actual distance travelled be x km.

Then, x        =       x + 20

10               14

14x = 10x + 200

4x = 200

x = 50 km.

8) A man travels 35 Km partly at 4 km/hr and partly at 5 km/hr. If he covers the former distance at 5 km/hr and latter distance at 4 km/hr, he could cover 1 km more in the same time. The time taken to cover the whole distance at the original rate is:

a) 9 hours

b) 7 hours

c) 4.5 hours

d) 8 hours

e) 3 hours

d) 8 hours

Explanation

Let ‘x’ and ’35­x’ be the distances travelled at 4 km/hr and 5 km/hr respectively Then time taken to cover 35 kms= (x/4) + ((35­x)/5)………..1

Now it is given that, he covers ‘x’ km at a speed of 5 km/hr and remaining distance at 4 km/hr. And in the same time, he covers 1 km extra.

Hence total distance in this case will be 36 km Time taken to cover 36 kms = (x/5) + ((36­x)/4)…………..2

Solving equations 1 and 2, we get x=20 km By substituting ‘x’ in equation 1

Time taken = 8hours

9) A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:

a) 100 kmph

b) 110 kmph

c) 120 kmph

d) 130 kmph

e) 125 kmph

c) 120 kmph

Explanation

Let speed of the car be x kmph.

Speed of train = 1.5x (75/x) ­ (75/1.5x) = (12.5/60) 25/x=12.5/60 x=120 kmph

10) A bus started its journey from Ramgarh and reached Devgarh in 44 minutes with its average speed of 50 km/hour. If the average speed of the bus is increased by 5 km/hour, how much time will it take to cover the same distance?

a)  40 minutes

b) 38 minutes

c) 36 minutes

d) 31 minutes

e)  49 minutes

a)  40 minutes