CRACK IBPS Clerk Prelims – Quadratic Equation day 11
Dear Bankersdaily Zealot ,
IBPS Clerk preliminary examination will be held in the month of December this year and you know the preparations are to be in sky level to reach the perfect destination of achieving the feat. Daily Quizzes enrich your preparations to the next level and you could also learn the mistakes at a daily pace.
This clerk planner is based on the previous year patterns and this daily planner which is going to be conducted for a period of 50 days will provide you the pace to attend the exam in the preliminary stage. This daily tests will be conducted in a quiz format as like the IBPS PO planner which we have conducted earlier.
Perpetual preparations will be the key to crack the exam. So ,don’t forget to check the daily quizzes on various topics in different sections in the planner. Do note the time , as we have allotted different timings for each section.
We hope these tests will entice you to practice more. If you face any issues in solving these problems, we are always here to help you. Please comment your doubts in the comments section , So that you get your doubts clarified instantly.
Do follow the tests regularly and we hope this will help you to crack the exams. At the end , you will also be able to attend free mock tests which will be in the same pattern as that of the exams.
After you finish the exams, please don’t forget to enter the details in the leader board, you may be in for a surprise at the end of this planner.
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IBPS Clerk Study Planner
Quadratic Equation day 11
Time : 10 Minutes
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Question 1 of 10
1. Question
1 pointsCategory: AptitudeDirections.15) In each of these questions, two equations I and II are given. You have to solve both the equation and give answer
I. x^{2}+22x+120=0
II.y^{2}20y300=0
Correct
I. x^{2}+22x+120=0
=>12+10=22
=>12×10=120
x= 12, 10
II.y^{2}20y300=0
=>30+10=20
=> 30×10=300
y=30, 10
Hence, I≤II
Incorrect
I. x^{2}+22x+120=0
=>12+10=22
=>12×10=120
x= 12, 10
II.y^{2}20y300=0
=>30+10=20
=> 30×10=300
y=30, 10
Hence, I≤II

Question 2 of 10
2. Question
1 pointsCategory: AptitudeDirections.15) In each of these questions, two equations I and II are given. You have to solve both the equation and give answer
I.x^{2}+20x+51=0
II.y^{2}15y+56=0
Correct
a
I.x^{2}+20x+51=0
=>17+3=20
=>17×3=51
x=17,3
II.y^{2}15y+56=0
=>78=15
=> 7×8=56
y=7,8
Hence, I<II
Incorrect
a
I.x^{2}+20x+51=0
=>17+3=20
=>17×3=51
x=17,3
II.y^{2}15y+56=0
=>78=15
=> 7×8=56
y=7,8
Hence, I<II

Question 3 of 10
3. Question
1 pointsCategory: AptitudeDirections.15) In each of these questions, two equations I and II are given. You have to solve both the equation and give answer
I.2x^{2}={(80x+396)/2}
II. y^{3}=(28y^{2}+819y)/7
Correct
c
I.2 x^{2}={(80x+396)/2}
x^{2}+20x+99=0
=> 9+11=20
=> 9×11=99
x=9, 11
II.y^{3}=(28y^{2}+819y)/7
y^{2}4y117=0
=> 13+9=4
=>13×9=117
y=13, 9
I≤II
Incorrect
c
I.2 x^{2}={(80x+396)/2}
x^{2}+20x+99=0
=> 9+11=20
=> 9×11=99
x=9, 11
II.y^{3}=(28y^{2}+819y)/7
y^{2}4y117=0
=> 13+9=4
=>13×9=117
y=13, 9
I≤II

Question 4 of 10
4. Question
1 pointsCategory: AptitudeDirections.15) In each of these questions, two equations I and II are given. You have to solve both the equation and give answer
I.x=√(3^{2}+4^{2} )
II. y=√(15^{2}+20^{2} )
Correct
a
I.x=√(3^{2}+4^{2} )
x=√25 =>x=5
II. y=√(15^{2}+20^{2} )
y=√625 =>y=25
Hence, I<II
Incorrect
a
I.x=√(3^{2}+4^{2} )
x=√25 =>x=5
II. y=√(15^{2}+20^{2} )
y=√625 =>y=25
Hence, I<II

Question 5 of 10
5. Question
1 pointsCategory: AptitudeDirections.15) In each of these questions, two equations I and II are given. You have to solve both the equation and give answer
I.5x^{2}+2x51=0
II.y^{2}+3y54=0
Correct
I.5x^{2}+2x51=0
=> 15+17=2
=> 15×17=255
x=15/5,17/5=3, 3.4
II.y^{2}+3y54=0
=> 15+18=3
=> 15×18=270
=>y=15/5, 18/5=3, 3.6
Hence, relationship can’t be established
Incorrect
I.5x^{2}+2x51=0
=> 15+17=2
=> 15×17=255
x=15/5,17/5=3, 3.4
II.y^{2}+3y54=0
=> 15+18=3
=> 15×18=270
=>y=15/5, 18/5=3, 3.6
Hence, relationship can’t be established

Question 6 of 10
6. Question
1 pointsCategory: AptitudeD.610) In each of these questions, two equations I and II are given. You have to solve both the equation and give answer
I. x=√(25^{2}15^{2} )
II.y=√(16^{2}+12^{2} )
Correct
e
 x=√(25^{2}15^{2} )
x=20
II.y=√(12^2+16^2 )
y=20
Hence, I=II
Incorrect
e
 x=√(25^{2}15^{2} )
x=20
II.y=√(12^2+16^2 )
y=20
Hence, I=II

Question 7 of 10
7. Question
1 pointsCategory: AptitudeD.610) In each of these questions, two equations I and II are given. You have to solve both the equation and give answer
I. x^{2}7x+12=0
II.y^2+17y+72=0
Correct
d
I.x^27x+12=0
=> 43=7
=> 4×3=12
x=4, 3
II.y^2+17y+72=0
=> 8+9=17
=> 8×9=72
=>y=8,9
Hence, I>II
Incorrect
d
I.x^27x+12=0
=> 43=7
=> 4×3=12
x=4, 3
II.y^2+17y+72=0
=> 8+9=17
=> 8×9=72
=>y=8,9
Hence, I>II

Question 8 of 10
8. Question
1 pointsCategory: AptitudeD.610) In each of these questions, two equations I and II are given. You have to solve both the equation and give answer
I.2x^{2}+13x+21=0
II.3y^2+11y+10=0
Correct
a
 2x^2+13x+21=0
=> 7+6=13
=>7×6=42
=>x=6/2,7/2=3, 3.5
II.3y^2+11y+10=0
=> 5+6=11
=> 5×6=30
=>y= 5/3, 6/3=1.67, 2
Hence, I<II
Incorrect
a
 2x^2+13x+21=0
=> 7+6=13
=>7×6=42
=>x=6/2,7/2=3, 3.5
II.3y^2+11y+10=0
=> 5+6=11
=> 5×6=30
=>y= 5/3, 6/3=1.67, 2
Hence, I<II

Question 9 of 10
9. Question
1 pointsCategory: AptitudeD.610) In each of these questions, two equations I and II are given. You have to solve both the equation and give answer
I. x^{3}={252x^3+308x^2 }/49x
II.y^{4}=256
Correct
e
 x^3={252x^3+308x^2 }/49x
7x^2+36x+44=0
=>14+22=36
=>14×22=308
x=14/7, 22/7=2, 3.14
II.y^4=256
y=∓4
Incorrect
e
 x^3={252x^3+308x^2 }/49x
7x^2+36x+44=0
=>14+22=36
=>14×22=308
x=14/7, 22/7=2, 3.14
II.y^4=256
y=∓4

Question 10 of 10
10. Question
1 pointsCategory: AptitudeD.610) In each of these questions, two equations I and II are given. You have to solve both the equation and give answer
I. 12x^{2}13x+3=0
II.6y^{2}+13y+7=0
Correct
 12x^213x+3=0
=> 94=13
=> 9×4=36
=>x=9/12,4/12=0.75, 0.33
II.6y^2+13y+7=0
=>6+7=13
=>6×7=42
y=6/6, 7/6= 1, 1.167
Hence, I>II
Incorrect
 12x^213x+3=0
=> 94=13
=> 9×4=36
=>x=9/12,4/12=0.75, 0.33
II.6y^2+13y+7=0
=>6+7=13
=>6×7=42
y=6/6, 7/6= 1, 1.167
Hence, I>II
IBPS CLERK Prelims Study Planner 2017
All the daily quizzes will be updated in the table in the above link, please do attend the quizzes in a daily manner so that, the chances of scoring in the preliminary examination of the IBPS Clerk 2017 is more. At the end, the ultimate aim is to score more and this may be a start to that achievement in the end.
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