PIPES AND CISTERN PART 2-LEARN SERIES
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PIPES AND CISTERN PART 2-LEARN SERIES
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Learning is a step by step process and you should gradually progress in that to ace the process. As you all know we have started a new Learn Series to help with your preparations for various exams like IBPS PO , IBPS RRB Scale I officer , IBPS RRB Office Assistant , IBPS Clerk , IBPS SO , SBI PO , SBI Clerk , SBI SO and many other exams in this type. Nevertheless this series will also contribute you all the tips and tricks to every miscellaneous sections and also all the important topics which are asked in the exams. If you haven’t looked at the Learn series , Please Click the below link to learn the new concepts.
INTRODUCTION TO PIPES AND CISTERN:
Today,we are going to look on Pipes and Cisterns.Before looking into Pipes and Cistern Part-2 Let us look into Pipe and Cistern Part-1
#.3. TYPE 3:
BASED ON EFFICIENCY:
1)A is thrice as efficient as B,If both the pipes are opened together the tank is filled in 2 days,then how long will it take to fill the tank only if Pipe B is Opened?
Let us Assume the capacity of Pipe B=10litre/day
Therefore,Capacity of Pipe A=3(B)
=3(10)=30litre/day
So When they are opened together,they can fill 40 litres/day
In 2 days,they can fill 80litres
If Pipe B is Opened then it will take-80/10=8 days
#.4. TYPE 4
BASED ON TIME:
1)There are 4 inlet Pipes namely A,B,C,D and their individual capacity to fill the tank is 20 hours,30 hours,40 hours and 50 hours respectively.A opens at 6.00 A.M.,B opens at 8.00 A.M.,C opens at 9 A.M. and D opens at 10 A.M.Find at what time the tank will be filled?
Total Capacity=LCM(20,30,40,50)=600 Litres
A’s Efficiency=600/20=30litres/hour
B’s Efficiency=600/30=20litres/hour
C’s Efficiency=600/40=15 litres/hour
D’s Efficiency =600/50=12 litres/hour
Given that,
A is opened at 6.00 A.M. till 10.00 A.M,it is opened for 4 hours
=30*4=120 litres/hour
B is opened at 8.00 A.M. till 10 A.M.,it is opened for 2 hours
=20*2=40 litres/hour
C is opened at 9.00 A.M. till 10 A.M., it is opened for 1 hour
=15*1=15 litres/hour
At 10.00 A.M
Three Pipes (A,B & C fill 175 litres)
Remaining Capacity in the tank=600-175=425 litres
This 475 litres is filled by all the 4 Inlet Pipes
Time=475/(30+20+15+12)
=475/77
=5 hours 30 Minutes
So from 10 A.M. it would take 5 hours 30 Minutes
The tank will be filled at 3.30 P.M
#.5 TYPE 5:
BASED ON PARTIAL TIME:
1)Two Pipes A & B fill the tank in 60 Minutes and 40 Minutes respectivley.How many minutes will it take to fill the tank from empty state if B is used for half the time & A and B used to fill Other half?
Let the Total Capacity=LCM(60,40)=120 Litres
Efficiency of A=120/60=2 litre/minute
Efficiency of B=120/40=3 litre/minute
Let the time taken by the pipes to fill the tank be X
Half the time=X/2 is used to fill the tank by B & Another half the time is used to fill the tank by A+B
=X/2(Filled by Pipe B)+X/2(Filled by Pipe A+B)
=(X/2)* (3) + (X/2)* (5)
=3(X/2) + 5(X /2)
=8(X/2)
We know that
Total Capacity=Time * Efficiency
120 = (X/2) * 8
240=X*8
30=X
Therefore, the tank is filled in 30 Minutes
