Problems on Ages for SBI PO : Aptitude set 2

Q.1) 0.3 decades ago, Vani was quadrice as old as her daughter.  0.6 decades hence, Vani’s age will beat twice of her daughter’s age by 1.5 decades. What is the proportion of the current ages of Vani and her daughter? [0.1 Decades =1 Year; quadrice = 4 times]

a) 17:5

b) 1:3

c) 5:17

d) 3:1

e) None of these

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vani-4 daughter=-9 —–(1)


vani-2 daughter=21—-(2)

solve (1)  and (2)

daughter=15 years

vani=51 years


Q.2) The ratio of the ages of Mala and Kala is 17:9. The total of their ages is 7.8 decades. The proportion of their ages after 0.7 decades will be [1 Decade = 10 years]

a) 18:29

b) 29:17

c) 17:32

d) 17:29

e) None of these

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Mala+kala=78 years


17 kala=702-9 kala


Mala=78-27=51 years

Required ratio=(51+7)/(27+7)=29/17=29:17

Q.3) If three times of the daughter’s age in years is included to the mother’s age, the total is 96 and if two times of the mother’s age is included to the daughter’s age, the total is 97. What is the difference between mother and daughter’s age?

a) 15 years

b) 18 years

c) 10 years

d) 20 years

e) None of these

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3 daughter+mother=96

daughter+2 mother=97

solve tha above equations,

daughter’s age=19 years

Mother’s age=39 years

difference=39-19=20 years

Q.4) The sum of the ages of 6 children born at the intervals of 4 years each is 174 years. What is the age of youngest child?

a) 21 years

b) 20 years

c) 19 years

d) 18 years

e) None of these

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Let the age of youngest child be x.





x=114/6=19 years

Q.5) Father is 4 times more aged than his daughter. If after 10 years, he would be 3 times of daughter’s age, then further after 15 years, how many times he would be of his daughter’s age?

a) 3 times

b) 2.14 times

c) 1.78 times

d) 3.2 times

e) 2.56 times

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Father=daughter+4 daughter=5daughter


==>5daughter-3 daughter=30-10

2 daughter=20

daughter=10 years

Father=50 years

After 25 years (10 years and further 15 years=25 years)

Required ratio=(50+25)/(10+25)=75/35=2.14 times

Q.6) Riya is thrice as old as her friend Mary. Mary is 6 years older than Rupa. In 2 years, Riya will be four times as old as Rupa. How old is Mary now?

a) 14 years

b) 12 years

c) 20 years

d) 18 years

e) None of these

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Riya=3 Mary—(1)



Substitute (1)in (3)

(3)==>3 mary+2=4 Rupa+8

3Mary-4 Rupa=6

Solve (2)  and (3)

Mary=18 yaers

Q.7) Grandfather is aged six times age of his granddaughter. Before three years, he would be 7 1/2  times of his granddaughter’s age. After 3 years, how many times would he be of his granddaughter’s age?

a) 6 3/16

b) 5 3/16

c) 5 1/16

d) 4 9/16

e) None of these

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Grandfather=6 granddaughter

Grandfather-3=15/2 (granddaughter-3)

2 grandfather-6=15 granddaughter-45

2(6 granddaughter)-6=15 granddaughter-45

3 grand daughter=39

granddaughter=13 years

Grandfather=78 years

After 3 years:

Required ratio=81/16=5 1/16  times

Q.8) Sabari’s mother was 24 years of age when he was born while his father was 34 years old when his sister four years younger to him was born. What is the difference between the ages of his parents?

a) 14 years

b) 8 years

c) 12 years

d) 9 years

e) 6 years

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Let age of Sabari be x.

Mother’s age x years ago 24, ( i.e.) mother-x=24





Required difference=father-mother

=34+x-4-24-x= 6years

Q.9) P is as much older than Q as he is younger than R. If the sum of the ages of P and R is 28 years, what is the difference between P and Q’s age?

a) 8 years

b) 4 years

c) 2 years

d) Cannot be determined

e) None of these

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P-Q=R-P —-(1)



Using the above equation ages of P, Q and R cannot be determined.

Q.10) The present ages of three persons A, B and C in proportions 21: 19: 11. Six years ago, the sum of their ages was 84. What is the difference between the present ages of A and C together and B?

a) 58 years

b) 26 years

c) 18 years

d) Cannot be determined

e) None of these

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age of A and C together=21x+11x=32×2=64

difference=64-38=26 years