TARGET SBI EXAM 2018: QUANTITATIVE- TIME & WORK
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TARGET SBI EXAM 2018: QUANTITATIVE- TIME & WORK
Dear Bankersdaily Aspirants,
Hope , Your preparation for SBI Clerk & PO exam 2018 is good . Since SBI Clerk & PO exam is a Two level which will be conducted in an online mode, Competition will be higher for this SBI Clerk & PO Exam and the most important thing , Current affairs section will be there in this exam. So aspirants have to concentrate in Four sections namely Aptitude, Reasoning, English, Current Affairs.
The person with high speed and very good accuracy only can crack this exam to taste the success. The candidates will be selected on the basis of performance in this online exam test. So the candidate with consistent hard work and regular practice will crack the exam very easily.
Here are some questions which will help you to identify your level of preparation.
Exam: SBI Clerk & PO Exam 2018
Topic: Time & work
Timing: 7 minutes
Q.1) Popeye started a work and left it after 9 days. The remaining work is completed by pope. So, the work gets completed in 25 days. Pope can alone finish the work in 30 days. Find the number of days in which Popeye can alone finish the work?
a) 14 days
b) 16 days
c) 18 days
d) 20 days
e) None of these
Q.2) Damon and Oliver work together in a farm, 25% of the work is completed in two days, if they work together. Due to some illness Oliver started at 1/3 rdof his efficiency and Damon starts working at twice his efficiency so that the work is completed in time, then what is the difference between the number of days in which both of them working together originally completed the work and number of days in which Damon alone would have completed the work if he works at his original efficiency?
a) 14days
b) 16days
c) 12days
d) 20days
e) None of these
Q.3) A certain number of people get together to contribute in the construction of a charity hospital. But for every month four people step out of this plan. Due to this the task is completed in 1/2 more years instead of one year. Then how many people were originally involved in this group?
a) 143
b) 102
c) 120
d) 133
e) None of these
Q.4) Pipe A can fill the tank in 30 hours when it works at 60% of its efficiency. Pipe B is one third as efficient as pipe A. How long will it take if both the pipes operate simultaneously at their 100% efficiency?
a) 14 hours
b) 12 hours
c) 11 hours
d) 10 hours
e) None of these
Q.5) 10 men can do 66.66% work in 10 days. 5 women can do 37.5% of same work in 9 days. Then in how many days can 80% of same work be done by 5 men and 2 women working together?
a) 14 Days
b) 15 days
c) 16 days
d) 18 days
e) None of these
Q.6)The amount of work to be done in a company is increased by 90%. By what percentage is it necessary to increase the number of workers to complete the new work in the same time as before if the new workers are 50% more efficient?
a) 75%
b) 60%
c) 50%
d) Cannot be determined
e) None of these
Q.7) 10 men can complete a work in 48 days. 16 women can complete the same piece of work in 60 days. 8 men and 20 women work together for 20 days, if only the women were to complete the remaining work in 4 days, then how many women would be required?
a) 40 women
b) 60 women
c) 80 women
d) 50 women
e) none of these
Q.8) Two farmers want to install tube wells of equal size in their farms. The first one employs 6 men and 4 women and gets the work completed in 14 days. The second one employs 8 men and 7 women and gets the work completed in 10 days to complete the same work. If a third farmer employs 1 man and 1 woman, how long would it take them to build the tube well for him?
a) 700/9 days
b) 500/9 days
c) 800/9 days
d) 75 days
e) None of these
Q.9) P, Q and R together can complete a piece of work in 8 days. Q and R started working and P joined them after 6 days and it took them another 6 days to complete the work. Find the number of days which p alone can complete the work?
a) 14 days
b) 12 days
c) 15 days
d) 18 days
e) None of these
Q.10) A chair manufacturer signs a contract to build 20000 chairs in 30 days and employs 40 men for the purpose. After 10 days, he finds that only 2000 chairs have been made. He employs some extra man to finish the work in 30 days. If the manufacturer had hired the extra men from the beginning , how many days would it have taken to complete the work?
a) 200/9 days
b) 100/3 days
c) 125/6 days
d) 34 days
e) None of these.
Answer Key
1.e
Let Popeye can alone complete the work in x days
Work done by Popeye in 9 days = 9/x of the complete work
Work left =1- 9/x=(x-9)/x
1/30 of the work is done by pope in 1 day
(x-9)/x of the work is done by Popeye in 1 day
30 =16× (x-9)/x
30x = 16x-144
14x = 144
X = 10 2/7
So, Popeye can alone complete the work in 10 2/7 days.
2.c
Let work done by Damon = x%
Work done by Oliver = y%
Total number of days required to complete the work =2× 100/25=8
X+y = 25/2
also, 2x+y/3=25/2
Solving them,
Y = 7.5 , x = 5
So, 100% of the work will be completed by Damon alone in 20 days.
Required difference = 20-8 =12 days.
3.b
Let the total number of people = x
12x = (x+(x-4)+(x-8)+(x-12)+(x-16)+(x-20)+….18 times)
12x = 18x – 4 (1+2+3+…17)
6x = 4×17× 18/2
X = 102
4.e
Pipe A can fill the tank when its efficiency is 100% =30× 60/100=18 hours
Pipe B can fill the tank in 54 hours.
When both the pipes operate simultaneously.
Time = (54×18)/(54+18)=13.5 hours.
5.c
10 men can do 2/3 of work in 10 days
10 men can do complete work in =10× 3/2=15 days
10M×15 = 150 men can do work in one day
5 Women can do 3/8 of work in 9 days
5 women can do complete work in =9× 8/3=24 days
5W×24 = 120 women can do work in one day
150M = 120 W
M = 4/5×W
5M =5× 4/5 W=4W
(4+2) W × days = 120 W
Days = 20 So, 80% of the work can be done in 20× 4/5=16 days
6.b
Let initially 100 units of work were done by 100 workers in 1 day, so efficiency of each worker was 1%
Now the work becomes 190 units.
So, they need to complete 190 units of work in 1 day.
So, the 100 workers do the 100 units of work
The remaining x new workers need to this 90 units of work in 1 day whose efficiency is 1.5 %each
So, number of new workers needed = 90/1.50=60 newworkersneeded.
So, percent by which workers need to be increased = 60/100×100=60%
7.b
10×M ×48 = W×16×60
M = 2W
So, 1 man work = 2 women work.
So, total work done by 8+10 = 18 men in 20 days = 18×20 = 360
Total required work = 10×48 =480
Work left =120
30 men can complete this in 4 days
So, women required = 60 [since 1 man work = 2 women work]
8.a
84 men days + 56 women days = 80 men days + 70 women days.
4 men days = 14 women days
1 man day = 3.5 women days
Total work = 80 men days + 70 women days = 350 women days.
1 man day + 1 women day = 4.5 women days
Number of days = 3500/45=700/9 days
9.b
One day’s work
1/p+1/Q+1/R=1/8
Also,
6 (1/P+1/Q+1/R)+ 6 (1/Q+1/R)= 1
6/8+6 (1/Q+1/R)= 1
1/Q+1/R=1/24
1/P=1/8-1/24
1/p=1/12
P= 12 days.
10.a
After 10 days, 400 men hours, only 10% of the work has been completed.
To complete the work in time, rest 90 % work must be completed in 20 days.
Man days required = 3600.
Hence he requires 180 men to work for 20 days
He must hire 140 extra men
If he hired 180 men from the beginning, number of days required = 4000/180=200/9 days.
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