TIME AND WORK PART-2-LEARN SERIES

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Also we are coming daily with different topics and if you haven’t checked our latest article on the Problems based on Time and Work Part 1,Please Click the link below

TIME AND WORK-PART 1-LEARN SERIES

INTRODUCTION TO TIME AND WORK:

There will be 1 or 2 Questions from this topic in all IBPS Exams.This topic is quite easy,Since Time and Work can be solved in Partial Method in our article we use LCM method to solve the problem in order to reduce the time consumption.There are 8 Basic types in Time and Work.Let us discuss each type with an example.

#.4 TYPE 4:

PROBLEMS BASED ON ALTERNATE DAYS:

In this type,we will be given individual Efficiency and the we are asked to find out the number of days when they work Alternatively.

1) A can complete the whole work in 10 days in the same time B can complete the work in 8 days.Then find in how many days they would complete the work if they work in alternate days?

Explanation

Given that,

A can complete the whole work in 10 days in the same time B can complete the work in 8 days

Total Work=LCM(10,8)=40

Efficiency of A=40/10=4 work/day

Efficiency of B=40/8=5 work/day

So,first day A will work and 2nd day B will work

So in 8 days they complete 36 works,Remaining 4 work is completed by A in the next day that is (9th

day)

Therefore,They will complete the task in 9 days

#.5. TYPE 5:

PROBLEMS BASED ON EFFICIENCY:

In this Type,we will be given any one’s individual efficiency and relation between the individual person and another person.(More Often they will indicate the relation between the two person as Twice,Thrice,..Sometimes with Percentage)

1) B can Complete the work in 10 days and A is twice as efficient as B.Find how long will A take to complete the work when he works alone?

Explanation

Given that,

B can Complete the work in 10 days

Total Work=LCM(2,10)=10 work

B’s Efficiency =10/10=1 work/day

Given that A is twice as efficient as B,

A=2(B)

A=2(1) work/day

So A can Complete the work in=10/2 = 5 days

#.6. TYPE 6:

PROBLEMS BASED ON FINDING INDIVIDUAL AND TOGETHER WORK FROM COMBINED WORK:

In this type ,we will be given the combined work and we are asked to find the individual work and the number of days when they work together.

1)A and B work together and complete the work in 12 days,B and C work together and complete the work in 15 days while C and A work together and complete the work in 20 days.Find in how many days they will complete the work if they work alone and if they work together?

Explanation

Given that,

A and B=12 days

B and C=15 days

C and A=20 days

Total Work=LCM(12,15,20)=60 work

Efficiency of A and B=60/12 = 5 work/day

Efficiency of B and C=60/15=4 work/day

Efficiency of C and A=60/20 = 3 work/day

By Solving the Efficiency,

we get,

Efficiency of A=2 work/day

Efficiency of B=3 work/day

Efficiency of C=1 work/day

Efficiency of A+B+C=6 work/day

So,the Time Taken by A=60/2=30 days

Time Taken by B=60/3 =20 days

Time Taken by C=60/1=60 days

Time Taken by A+B+C=60/6=10 days

TIME AND WORK PART-2-LEARN SERIES

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