PRACTICE QUIZ ON PROBLEMS BASED ON PERMUTATIONS
Hi Bankersdaily Aspirants,
Aspirants,As you all know that IBPS RRB is going to held shortly,we are in the right time for our preparation.Keeping Neophyte in mind we are discussing each topic in Aptitude Section.
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Permutation Quiz
No.of Questions: 10
Time : 10 Minutes
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Question 1 of 10
1. Question
1 pointsCategory: Aptitude1)If a class has 8 students, how many different arrangements can 5 students give a presentation to the class?
Correct
Explanation:
P(8,5)=8!/(85)!=8!/3!
=6720 Ways
Incorrect
Explanation:
P(8,5)=8!/(85)!=8!/3!
=6720 Ways

Question 2 of 10
2. Question
1 pointsCategory: Aptitude2)How many staircase path there are from the origin (0,0) to (4,3),the stair case moves towards right one step and towards upward one step?
Correct
Explanation:
From the Above Diagram it is clear that there is 4 Right Turns and 3 Up Turns
=7!/4!*3!
=35 Paths
Incorrect
Explanation:
From the Above Diagram it is clear that there is 4 Right Turns and 3 Up Turns
=7!/4!*3!
=35 Paths

Question 3 of 10
3. Question
1 pointsCategory: Aptitude3)How many numbers of four digits can be formed with the digits 1,2,3,4 and 5?
Correct
Explanation:
Number of Digits =5
Number of Places to be filled up=4
Required Number=5! P (54)! =5*4*3*2=120
Incorrect
Explanation:
Number of Digits =5
Number of Places to be filled up=4
Required Number=5! P (54)! =5*4*3*2=120

Question 4 of 10
4. Question
1 pointsCategory: Aptitude4)In a class of 10 students,there are 3 girls.In how many different ways can they be arranged in a row such that no two of the three girls are consecutive?
Correct
Explanation:
There is no Restriction on Arrangements of number of boys,
Therefore, they are arranged in 7! ways
There are 3 girls they are not consecutive to each other=8!/(85)1=(8!/3!) * 7! =
Incorrect
Explanation:
There is no Restriction on Arrangements of number of boys,
Therefore, they are arranged in 7! ways
There are 3 girls they are not consecutive to each other=8!/(85)1=(8!/3!) * 7! =

Question 5 of 10
5. Question
1 pointsCategory: Aptitude5)In how many ways 4 boys and 4 girls can be seated in a row so that boys and girls are alternate?
Correct
Explanation:
Given that they Sit Alternate to each other
=2(4!*4!)
=1152 Ways
Incorrect
Explanation:
Given that they Sit Alternate to each other
=2(4!*4!)
=1152 Ways

Question 6 of 10
6. Question
1 pointsCategory: Aptitude6)In how many ways 4 boys and 3 girls can be seated in a row so that they are alternate?
Correct
Explanation:
The number of possible ways are 4! * 3! =144 Ways
Incorrect
Explanation:
The number of possible ways are 4! * 3! =144 Ways

Question 7 of 10
7. Question
1 pointsCategory: Aptitude7)Find the number of permutations of the letters of the word “PreUniversity”?
Correct
Explanation:
Required number of Permutations=13!/(2! * 2! * 2!)
Incorrect
Explanation:
Required number of Permutations=13!/(2! * 2! * 2!)

Question 8 of 10
8. Question
1 pointsCategory: Aptitude8)How many different words can be formed with the letters of the word ‘University’;So that all the vowels are together?
Correct
Explanation:
Possible number of ways=7! * (4!/2!)=60480 ways
Incorrect
Explanation:
Possible number of ways=7! * (4!/2!)=60480 ways

Question 9 of 10
9. Question
1 pointsCategory: Aptitude9)A library has 2 books each having three copies and three other books each having two copies.In how many ways can all these books be arranged in a shelf so that copies of the same books are not separated?
Correct
Explanation:
Let us Assume all copies of the same book as one book,now we have only 5 books
These 5 books can be arranged in 5 ! ways.But all copies of the same boo being identical can be arranged in only one way
Therefore, The Required number of ways=5! * 1! *1!*1!*1!*1!=120
Incorrect
Explanation:
Let us Assume all copies of the same book as one book,now we have only 5 books
These 5 books can be arranged in 5 ! ways.But all copies of the same boo being identical can be arranged in only one way
Therefore, The Required number of ways=5! * 1! *1!*1!*1!*1!=120

Question 10 of 10
10. Question
1 pointsCategory: Aptitude10) In how many different ways can the letter of the word JUDGE be arranged so that the vowels always come together?
Correct
Explanation:
Required Ways=4! * 2!=48 ways
Incorrect
Explanation:
Required Ways=4! * 2!=48 ways
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