**PRACTICE QUIZ ON PROBLEMS BASED ON PERMUTATIONS**

**Hi Bankersdaily Aspirants,**

Aspirants,As you all know that IBPS RRB is going to held shortly,we are in the right time for our preparation.Keeping Neophyte in mind we are discussing each topic in Aptitude Section.

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**Permutation Quiz **No.of Questions: 10

Time : 10 Minutes

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- Question 1 of 10
##### 1. Question

1 pointsCategory: Aptitude1)If a class has 8 students, how many different arrangements can 5 students give a presentation to the class?

Correct**Explanation:**P(8,5)=8!/(8-5)!=8!/3!

=

**6720 Ways**Incorrect**Explanation:**P(8,5)=8!/(8-5)!=8!/3!

=

**6720 Ways** - Question 2 of 10
##### 2. Question

1 pointsCategory: Aptitude2)How many stair-case path there are from the origin (0,0) to (4,3),the stair case moves towards right one step and towards upward one step?

Correct**Explanation:**From the Above Diagram it is clear that there is 4 Right Turns and 3 Up Turns

=7!/4!*3!

=35 Paths

Incorrect**Explanation:**From the Above Diagram it is clear that there is 4 Right Turns and 3 Up Turns

=7!/4!*3!

=35 Paths

- Question 3 of 10
##### 3. Question

1 pointsCategory: Aptitude3)How many numbers of four digits can be formed with the digits 1,2,3,4 and 5?

Correct**Explanation:**Number of Digits =5

Number of Places to be filled up=4

Required Number=5! P (5-4)! =5*4*3*2=120

Incorrect**Explanation:**Number of Digits =5

Number of Places to be filled up=4

Required Number=5! P (5-4)! =5*4*3*2=120

- Question 4 of 10
##### 4. Question

1 pointsCategory: Aptitude4)In a class of 10 students,there are 3 girls.In how many different ways can they be arranged in a row such that no two of the three girls are consecutive?

CorrectExplanation:

There is no Restriction on Arrangements of number of boys,

Therefore, they are arranged in 7! ways

There are 3 girls they are not consecutive to each other=8!/(8-5)1=(8!/3!) * 7! =

IncorrectExplanation:

There is no Restriction on Arrangements of number of boys,

Therefore, they are arranged in 7! ways

There are 3 girls they are not consecutive to each other=8!/(8-5)1=(8!/3!) * 7! =

- Question 5 of 10
##### 5. Question

1 pointsCategory: Aptitude5)In how many ways 4 boys and 4 girls can be seated in a row so that boys and girls are alternate?

Correct**Explanation:**Given that they Sit Alternate to each other

=2(4!*4!)

=1152 Ways

Incorrect**Explanation:**Given that they Sit Alternate to each other

=2(4!*4!)

=1152 Ways

- Question 6 of 10
##### 6. Question

1 pointsCategory: Aptitude6)In how many ways 4 boys and 3 girls can be seated in a row so that they are alternate?

Correct**Explanation:**The number of possible ways are 4! * 3! =

**144 Ways**Incorrect**Explanation:**The number of possible ways are 4! * 3! =

**144 Ways** - Question 7 of 10
##### 7. Question

1 pointsCategory: Aptitude7)Find the number of permutations of the letters of the word “Pre-University”?

Correct**Explanation:**Required number of Permutations=13!/(2! * 2! * 2!)

Incorrect**Explanation:**Required number of Permutations=13!/(2! * 2! * 2!)

- Question 8 of 10
##### 8. Question

1 pointsCategory: Aptitude8)How many different words can be formed with the letters of the word ‘University’;So that all the vowels are together?

Correct**Explanation:**Possible number of ways=7! * (4!/2!)=

**60480 ways**Incorrect**Explanation:**Possible number of ways=7! * (4!/2!)=

**60480 ways** - Question 9 of 10
##### 9. Question

1 pointsCategory: Aptitude9)A library has 2 books each having three copies and three other books each having two copies.In how many ways can all these books be arranged in a shelf so that copies of the same books are not separated?

CorrectExplanation:

Let us Assume all copies of the same book as one book,now we have only 5 books

These 5 books can be arranged in 5 ! ways.But all copies of the same boo being identical can be arranged in only one way

Therefore, The Required number of ways=5! * 1! *1!*1!*1!*1!=120

IncorrectExplanation:

Let us Assume all copies of the same book as one book,now we have only 5 books

These 5 books can be arranged in 5 ! ways.But all copies of the same boo being identical can be arranged in only one way

Therefore, The Required number of ways=5! * 1! *1!*1!*1!*1!=120

- Question 10 of 10
##### 10. Question

1 pointsCategory: Aptitude10) In how many different ways can the letter of the word JUDGE be arranged so that the vowels always come together?

Correct**Explanation:**Required Ways=4! * 2!=48 ways

Incorrect**Explanation:**Required Ways=4! * 2!=48 ways