# Crack IBPS PO : Data Interpretation Day 5

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**IBPS PO Study Planner**

**Data Interpretation Day 7 No.of Questions: 10 Time : 10 minutes All the Best!!!**

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- Question 1 of 10
##### 1. Question

1 pointsCategory: Aptitude**D.1-5)**Study the following information carefully and answer the following questions.The following bar graph shows investment of 4 persons A, B, C and D.(in thousands)

**What is the average investment of C made during all the given years?**Correctb

Average investment of C= (21+15+11+19+18)/5=84/5=16.8( thousand)

Incorrectb

Average investment of C= (21+15+11+19+18)/5=84/5=16.8( thousand)

- Question 2 of 10
##### 2. Question

1 pointsCategory: Aptitude**D.1-5)**Study the following information carefully and answer the following questions.The following bar graph shows investment of 4 persons A, B, C and D.(in thousands)

**What is the ratio of investment of A to that of B, both during 2012 and 2013 taken together?**Correctd

Required ratio=(12+15):(11+16)=27: 27=1:1

Incorrectd

Required ratio=(12+15):(11+16)=27: 27=1:1

- Question 3 of 10
##### 3. Question

1 pointsCategory: Aptitude**D.1-5)**Study the following information carefully and answer the following questions.The following bar graph shows investment of 4 persons A, B, C and D.(in thousands)

**If total profit at the end of 2014 is Rs.55000 then what is the share of A and B together?**Correcta

Profit ratio of A, B, C and D=78: 78: 84: 90

=13:13:14:15

Share of A and B together= 55000/55×26=Rs.26000

Incorrecta

Profit ratio of A, B, C and D=78: 78: 84: 90

=13:13:14:15

Share of A and B together= 55000/55×26=Rs.26000

- Question 4 of 10
##### 4. Question

1 pointsCategory: Aptitude**D.1-5)**Study the following information carefully and answer the following questions.The following bar graph shows investment of 4 persons A, B, C and D.(in thousands)

**Investment of D during 2013 is what percentage of to total investment during the same year?**Correctc

Required percentage= 20/(15+16+19+20)×100=28.57%

Incorrectc

Required percentage= 20/(15+16+19+20)×100=28.57%

- Question 5 of 10
##### 5. Question

1 pointsCategory: Aptitude**D.1-5)**Study the following information carefully and answer the following questions.The following bar graph shows investment of 4 persons A, B, C and D.(in thousands)

**If A and B are remain in the partnership till 2014 while C joins after two years and D joins after three years, then what is the ratio of their profit?**Correcte

Required ratio

=(20+15+12+15+16): (22+14+11+16+15): (11+19+18): (20+21)

=78:78:48:41

Incorrecte

Required ratio

=(20+15+12+15+16): (22+14+11+16+15): (11+19+18): (20+21)

=78:78:48:41

- Question 6 of 10
##### 6. Question

1 pointsCategory: Aptitude**D.6-10)**Study the following graph carefully and answer the questions given below:Pie chart shows the percentage of the number of bags sold by shopkeeper K during six months

Total number of bags sold = 30000

The respective ratio between the number of bags sold of shopkeeper K and P during six months

Month Ratio (K:P) January 5:7 February 2:3 March 5:4 April 11:9 May 3:7 June 4:1 **What is the ratio between the number of bags sold by shopkeeper P to number of bags sold by shopkeeper K in the month of March and May together?**Correct(a)

Number of bags sold by shopkeeper P in March= 30000×12/100×4/9=1600

Number of bags sold by shopkeeper P in May= 30000×17/100×7/10=3570

Number of bags sold by shopkeeper K in March= 30000×12/100×5/9=2000

Number of bags sold by shopkeeper K in May= 30000×17/100×3/10=1530

Required ratio = (1600+3570): (2000+1530)=5170: 3530

= 517:353

(a)

Number of bags sold by shopkeeper P in March= 30000×12/100×4/9=1600

Number of bags sold by shopkeeper P in May= 30000×17/100×7/10=3570

Number of bags sold by shopkeeper K in March= 30000×12/100×5/9=2000

Number of bags sold by shopkeeper K in May= 30000×17/100×3/10=1530

Required ratio = (1600+3570): (2000+1530)=5170: 3530

= 517:353

Incorrect(a)

Number of bags sold by shopkeeper P in March= 30000×12/100×4/9=1600

Number of bags sold by shopkeeper P in May= 30000×17/100×7/10=3570

Number of bags sold by shopkeeper K in March= 30000×12/100×5/9=2000

Number of bags sold by shopkeeper K in May= 30000×17/100×3/10=1530

Required ratio = (1600+3570): (2000+1530)=5170: 3530

= 517:353

(a)

Number of bags sold by shopkeeper P in March= 30000×12/100×4/9=1600

Number of bags sold by shopkeeper P in May= 30000×17/100×7/10=3570

Number of bags sold by shopkeeper K in March= 30000×12/100×5/9=2000

Number of bags sold by shopkeeper K in May= 30000×17/100×3/10=1530

Required ratio = (1600+3570): (2000+1530)=5170: 3530

= 517:353

- Question 7 of 10
##### 7. Question

1 pointsCategory: Aptitude**D.6-10)**Study the following graph carefully and answer the questions given below:Pie chart shows the percentage of the number of bags sold by shopkeeper K during six months

Total number of bags sold = 30000

The respective ratio between the number of bags sold of shopkeeper K and P during six months

Month Ratio (K:P) January 5:7 February 2:3 March 5:4 April 11:9 May 3:7 June 4:1 **What is the average number of bags sold by shopkeeper P in the given months together?**Correct(c)

Number of bags sold by shopkeeper P in January= 30000×20/100×7/12=3500

Number of bags sold by shopkeeper P in February= 30000×18/100×3/5=3240

Number of bags sold by shopkeeper P in March= 30000×12/100×4/9=1600

Number of bags sold by shopkeeper P in April= 30000×15/100×9/20=2025

Number of bags sold by shopkeeper P in May= 30000× 17/100×7/10=3570

Number of bags sold by shopkeeper P in June= 30000×18/100×1/5=1080

Required average = (3500+3240+1600+2025+3570+1080)/6=2502.5

Incorrect(c)

Number of bags sold by shopkeeper P in January= 30000×20/100×7/12=3500

Number of bags sold by shopkeeper P in February= 30000×18/100×3/5=3240

Number of bags sold by shopkeeper P in March= 30000×12/100×4/9=1600

Number of bags sold by shopkeeper P in April= 30000×15/100×9/20=2025

Number of bags sold by shopkeeper P in May= 30000× 17/100×7/10=3570

Number of bags sold by shopkeeper P in June= 30000×18/100×1/5=1080

Required average = (3500+3240+1600+2025+3570+1080)/6=2502.5

- Question 8 of 10
##### 8. Question

1 pointsCategory: Aptitude**D.6-10)**Study the following graph carefully and answer the questions given below:Pie chart shows the percentage of the number of bags sold by shopkeeper K during six months

Total number of bags sold = 30000

The respective ratio between the number of bags sold of shopkeeper K and P during six months

Month Ratio (K:P) January 5:7 February 2:3 March 5:4 April 11:9 May 3:7 June 4:1 **If 40% of the bags sold with discount by shopkeeper K during January and June month, how many bags were sold without any discount?**Correct(e)

Total number of bags sold by shopkeeper K during January and June without any discounts =(20/100×30000×5/12×60/100)+(18/100×30000×4/5×60/100)

=1500+2592=4092

Incorrect(e)

Total number of bags sold by shopkeeper K during January and June without any discounts =(20/100×30000×5/12×60/100)+(18/100×30000×4/5×60/100)

=1500+2592=4092

- Question 9 of 10
##### 9. Question

1 pointsCategory: Aptitude**D.6-10)**Study the following graph carefully and answer the questions given below:Pie chart shows the percentage of the number of bags sold by shopkeeper K during six months

Total number of bags sold = 30000

The respective ratio between the number of bags sold of shopkeeper K and P during six months

Month Ratio (K:P) January 5:7 February 2:3 March 5:4 April 11:9 May 3:7 June 4:1 **What is the difference between the number of bags sold by shopkeeper P in the month of April, May and June together and the number of bags sold by shopkeeper K in the month of January, February and March together?**Correct(d)

Number of bags sold by shopkeeper P in April= 30000× 15/100×9/20=2025

Number of bags sold by shopkeeper P in May= 30000×17/100×7/10=3570

Number of bags sold by shopkeeper P in June= 30000×18/100×1/5=1080

Number of bags sold by shopkeeper K in January= 30000×20/100×5/12=2500

Number of bags sold by shopkeeper K in February= 30000×18/100×2/5=2160

Number of bags sold by shopkeeper K in March= 30000×12/100×5/9=2000

Require difference =(2025+3570+1080)-(2500+2160+2000)=15

Incorrect(d)

Number of bags sold by shopkeeper P in April= 30000× 15/100×9/20=2025

Number of bags sold by shopkeeper P in May= 30000×17/100×7/10=3570

Number of bags sold by shopkeeper P in June= 30000×18/100×1/5=1080

Number of bags sold by shopkeeper K in January= 30000×20/100×5/12=2500

Number of bags sold by shopkeeper K in February= 30000×18/100×2/5=2160

Number of bags sold by shopkeeper K in March= 30000×12/100×5/9=2000

Require difference =(2025+3570+1080)-(2500+2160+2000)=15

- Question 10 of 10
##### 10. Question

1 pointsCategory: Aptitude**D.6-10)**Study the following graph carefully and answer the questions given below:Pie chart shows the percentage of the number of bags sold by shopkeeper K during six months

Total number of bags sold = 30000

The respective ratio between the number of bags sold of shopkeeper K and P during six months

Month Ratio (K:P) January 5:7 February 2:3 March 5:4 April 11:9 May 3:7 June 4:1 **The number of bags sold by shopkeeper P during the month January is approximately by what percentage of the number of bags sold by shopkeeper K during the month June?**Correct(d)

Required percentage = (30000×20/100×7/12)/(30000×18/100×4/5) ×100= 3500/4320×100~ 81%

Incorrect(d)

Required percentage = (30000×20/100×7/12)/(30000×18/100×4/5) ×100= 3500/4320×100~ 81%

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