# Case Study / Caselet Questions for SBI PO Prelims Exam 2018

Dear Bankersdaily Aspirants,

SBI PO Prelims Exam 2018 is happening Tomorrow (Day 2) and in the Day 1 of SBI PO 2018 , Caselet/ Case Study Questions were asked. We were getting many requests for the Caselet / Case Study Sets for practice. We know this is the right time to examine your knowledge and test your skills in the Caselet Sets.

Attempt these Questions now to enhance your preparations to the Next level. Aspirants can find the SBI PO Prelims Exam – Review & Analysis of 1st July, 2018 in the links given below.

## Slot 4

Set (1-5) Read the following information and answers the given questions.

In a college, three programming languages are taught. Out of 1200 students, each one is required to study at least one of the three languages which are BASIC, COBAL and C. 40 students study all the three languages. 404 students study only C, 222 students study only BASIC, 500 students study COBAL, 114 students study both C and BASIC and 388 students study only COBAL.

1. How many students study two programming languages only such that at least one of the two languages is COBAL?

(A) 36

(B) 72

(C) 48

(D) 60

(E) 80

2. What is the number of students who study exactly two languages?

(A) 146

(B) 126

(C) 136

(D) 156

(E) 132

3. If the number of students study C language is 554, then what is the number of students study BASIC language?

(A) 348

(B) 372

(C) 336

(D) 308

(E) 318

4. If the number of students study BASIC language is 384, then what is the number of students study both COBOL and C languages?

(A) 24

(B) 36

(C) 72

(D) 48

(E) 64

5. What is the total number of students study C and BASIC languages?

(A) 720

(B) 772

(C) 812

(D) 782

(E) 834

Set (6 – 10) Read the following information and answers the given questions.

Dhoni and kohli study in the same school and go to school by walk. Dhoni starts from his house at 8.20 a.m. usually. On Tuesday he walked at 6 km/hr and was late by 8 minutes. On Wednesday he increased his speed to 8 km/hr and reached 8 minutes early. Kholi starts from his house at 8.10 a.m. usually. On Tuesday, he walked at 6.5 km/hr and was late by 12 minutes. On Wednesday he increased his speed to 8 km/hr and reached 6 minutes early.

6. What is the distance from Dhoni house to School?

(A) 6.4 km

(B) 7.2 km

(C) 5.6 km

(D) 7.6 km

(E) None of these

7. If both Dhoni and Kohli reached the school at the right time on Thursday, what were their walking speeds respectively?

(A) 48/7 km/hr, 52/7 km/hr

(B) 49/8 km/hr, 27/4 km/hr

(C) 57/7 km/hr, 31/5 km/hr

(D) 61/9 km/hr, 33/7

(E) None of these

8. What is the distance from kohli house to school?

(A) 8 km

(B) 9.6 km

(C) 9.8 km

(D) 10.4 km

(E) 10.2 km

SET (9-11) Read the following information and answers the questions.

There are four mixtures of water and milk.

Mixture A contains water and milk in the ratio 5: 4

Mixture B contains water and milk in the ratio 1: 5

Mixture C contains water and milk in the ratio 4:5

Mixture B and C mixed in 1: 3 result in mixture D.

9. What is the ratio of water and milk in mixture D?

(A) 3:5

(B) 3:4

(C) 4: 3

(D) 5: 3

(E) 2: 3

10. In what ratio should mixture A and B be mixed in order to get mixture C?

(A) 2:3

(B) 3: 4

(C) 1:5

(D) 5: 2

(E) 2: 5

11. In what ratio should mixtures A and D be mixed so that the volumes of water and milk are equal in the resultant mixture?

(A) 4: 7

(B) 7: 4

(C) 9: 4

(D) 6:1

(E) 1:2

Set (12 – 16) Study the following passage and answers the questions.

A certain number of students are interested in different activities like Singing, painting and dancing. 240 of them are interested in only painting. The total number of students who are interested in both painting and singing is 6/5 of the number of students who are interested in only painting. 5/8 of the number of students interested in both painting and singing are interested in all the three activities. The number of students interested in both singing and dancing but not painting is the average of the number of students who are interested in only painting and the number of students who are interested in all the three activities. The number of students who are interested in only dancing is 30% more than the number of students who are interested in both singing and dancing but not painting. The number of students interested in singing is same as the number of students interested in dancing. The number of students interested in only singing is half the number of students interested in more than one activity.

12. How many students like any of the given activities?

(A) 1472

(B) 1498

(C) 1512

(D) 1523

(E) 1533

13. What percentage of the total number of students likes all the three activities?

(A) 12.23%

(B) 11.90%

(C) 13.33%

(D) 16.67%

(E) 14.28%

14. What is the difference between the number of people who like dancing but not painting and the number of people who like painting but not dancing?

(A) 145

(B) 125

(C) 175

(D) 135

(E) 150

15. How many students like exactly two activities?

(A) 477

(B) 457

(C) 468

(D) 448

(E) 486

16. How many students like only Dancing?

(A) 273

(B) 265

(C) 257

(D) 270

(E) 250

SET (17 – 20) Study the following paragraph and answer the questions.

In Chennai Anna University, the first year is a foundation program for all the students after which in second year the students can-opt for their major subject. In 2015, only 80% of the students passed the first year examination and all of those who passed joined in the second year. In 2015, only 20% of students of first year who passed the first year examination joined physical sciences, 30% joined the Arts stream, 40% joined commerce stream while others joined computer stream. Apart from those, some students from other universities who passed their first year also joined Chennai Anna University. Such students were 30% of the number of first year students from Chennai Anna University who passed 2015 examination. The number of students from other universities across physical sciences, Arts, commerce and computer streams are joined in Chennai Anna University were in ratio 1: 3: 4: 2 respectively. In 2015, the number of students in Arts stream in Chennai Anna University in second year was 780.

17. In 2015, what percent of science stream students in second year in Chennai Anna University were first year science stream students who pass-outs from Chennai Anna University only? (Approximately)

(A) 87%

(B) 83%

(C) 92%

(D) 77%

(E) 73%

18. What is the total number of students promoted to second year?

(A) 2500

(B) 2250

(C) 2000

(D) 1500

(E) 1750

19. What is the total number of students studying in Chennai Anna University in second year?

(A) 2000

(B) 2600

(C) 2300

(D) 2700

(E) 2400

20. What was the number of students in second year commerce stream in Chennai Anna University in 2015?

(A) 1040

(B) 1080

(C) 1050

(D) 1150

(E) 1200

21. What is the number of students from other universities joining Chennai Anna University in 2015?

(A) 500

(B) 600

(C) 800

(D) 400

(E) 1000

Aspirants can check the answers for the above Questions from the below given ones.

1. (b)

Only two languages (One is COBOL)= 1200- (404+388+222+40+74)= 72

2. (a)

COBOL+BASIC and COBOL+C = 1200- (404+388+222+40+74)= 72

Exactly any two languages only = = 72+74 = 146

3. ( b )

COBOL+BASIC and COBOL+C = 1200- (404+388+222+40+74)= 72

C language= 404+74+40+(72-COBOL language and BASIC only)=554

Therefore, COBOL+BASIC =( 404+74+40+72)-554=36

Required total = 222+74+40+36 = 372

4. (e)

BASIC language = 222+74+40+(BASIC and COBOL only)=384

BASIC and COBOL only=384-(222+74+40)=48

Therefore, COBOL and C only=72(BASIC and COBOL only + COBOL and C only) – 48=24

Both COBOL and C = 40+24=64

5. (c)

Number of students study C and BASIC language = Total-COBOL only

=1200-388=812

6. (a)

Dhoni:

Let the distance between his house and school be Y km

Time taken when he walks at 6 km/hr = Y/6

Time taken when he walks at 8 km/hr = Y/8

In the first case he is late by 8 minutes while in the second case he reaches early by 8 minutes. So, time difference = 16 minutes.

So, we have,

Y = 6.4 km

7. (a)

Dhoni:

Let the distance between his house and school be Y km

Time taken when he walks at 6 km/hr = Y/6

Time taken when he walks at 8 km/hr = Y/8

In the first case he is late by 8 minutes while in the second case he reaches early by 8 minutes. So, time difference = 16 minutes.

So, we have,

Y = 6.4 km

Dhoni needs to cover 6.4 km

In 1st case he walks at 6 km/hr

Required time = 64 minutes

Therefore, 8 minutes late, = 64-8 = 56 minutes.

Required speed =

Kohli:

Let the distance between his house and school be Z km

Time taken when he walks at 6.5 km/hr = Z/6.5

Time taken when he walks at 8 km/hr = Z/8

In the first case he is late by 12 minutes while in the second case he reaches early by 6 minutes. So, time difference = 18 minutes.

So, we have,

Z = 10.4 km

In 2nd case he walks at 8 km/hr

Required time == 78 minutes

Therefore, 6 minutes late, = 78+6 = 84 minutes.

Required speed

8. (d)

Kohli:

Let the distance between his house and school be Z km

Time taken when he walks at 6.5 km/hr = Z/6.5

Time taken when he walks at 8 km/hr = Z/8

In the first case he is late by 12 minutes while in the second case he reaches early by 6 minutes. So, time difference = 18 minutes.

So, we have,

Z = 10.4 km

9. (a)

water: milk = 4: 5

Mixture D is obtaining by mixing B and C in the ratio 1: 3

Let x litres of B and 3x litres of C be mixed.

10. ( d)

water: milk = 4: 5

Required ratio= 5:2

11. (c)

water: milk = 4: 5

Mixture D is obtaining by mixing B and C in the ratio 1: 3

Let x litres of B and 3x litres of C be mixed.

Required ratio= (1/8 ) : (1/18) =18:8=9:4

12. (c)

The total number of students who are interested in both painting and singing =240×(6/5)=288

The number of students interested in all the three activities = (5/8)×288= 180

Number of students who are interested in only painting and singing but not in dancing = 288-180 = 108

The number of students interested in both singing and dancing but not painting = (240+180)/2 = 210

The number of students who are interested in only dancing = 210×1.3= 273

Let, the number of students interested in only singing = x

Let, the number of students interested in both dancing and painting but not singing = y

108+180+210+x = 210+180+y+273

x-y = 165

Also,

108+180+y+ 210 = 2x

498+y=2x

Y = 2x-498

x-2x-498 = 165

498-165 = x

333 = x

Y = 168

Required total = 240+108+168+180+210+273+333 = 1512

13. (b)

The total number of students who are interested in both painting and singing =240 × (6/5)=288

The number of students interested in all the three activities =  (5/8) × 288= 180

Number of students who are interested in only painting and singing but not in dancing = 288-180 = 108

The number of students interested in both singing and dancing but not painting = (240+180)/2 = 210

The number of students who are interested in only dancing = 210×1.3= 273

Let, the number of students interested in only singing = x

Let, the number of students interested in both dancing and painting but not singing = y

108+180+210+x = 210+180+y+273

x-y = 165

Also,

108+180+y+ 210 = 2x

498+y=2x

Y = 2x-498

x-2x-498 = 165

498-165 = x

333 = x

Y = 168

Required % =

14. (d)

The total number of students who are interested in both painting and singing =240× ( 6/5)=288

The number of students interested in all the three activities =( 5/8 ) ×288= 180

Number of students who are interested in only painting and singing but not in dancing = 288-180 = 108

The number of students interested in both singing and dancing but not painting = (240+180)/2 = 210

The number of students who are interested in only dancing = 210×1.3= 273

Let, the number of students interested in only singing = x

Let, the number of students interested in both dancing and painting but not singing = y

108+180+210+x = 210+180+y+273

x-y = 165

Also,

108+180+y+ 210 = 2x

498+y=2x

Y = 2x-498

x-2x-498 = 165

498-165 = x

333 = x

Y = 168

Required difference = 273+210-(240+108)=135

15. (e)

The total number of students who are interested in both painting and singing =240× (6/5)=288

The number of students interested in all the three activities = (5/8) ×288= 180

Number of students who are interested in only painting and singing but not in dancing = 288-180 = 108

The number of students interested in both singing and dancing but not painting = (240+180)/2 = 210

The number of students who are interested in only dancing = 210×1.3= 273

Let, the number of students interested in only singing = x

Let, the number of students interested in both dancing and painting but not singing = y

108+180+210+x = 210+180+y+273

x-y = 165

Also,

108+180+y+ 210 = 2x

498+y=2x

Y = 2x-498

x-2x-498 = 165

498-165 = x

333 = x

Y = 168

Required total = 108+168+210 = 486

16. (a)

The total number of students who are interested in both painting and singing =240× (6/5)=288

The number of students interested in all the three activities = (5/8) ×288= 180

Number of students who are interested in only painting and singing but not in dancing = 288-180 = 108

The number of students interested in both singing and dancing but not painting = (240+180)/2 = 210

The number of students who are interested in only dancing = 210×1.3= 273

Let, the number of students interested in only singing = x

Let, the number of students interested in both dancing and painting but not singing = y

108+180+210+x = 210+180+y+273

x-y = 165

Also,

108+180+y+ 210 = 2x

498+y=2x

Y = 2x-498

x-2x-498 = 165

498-165 = x

333 = x

Y = 168

Required total = 273

17. (a)

Let us assume the total number of first year students in Chennai Anna university be X

Then, as per data, number of students who passed in first year = 0.8X

Students in physical science, commerce, arts and computer stream becomes: 0.16X, 0.32X, 0.24X, 0.08X respectively.

Total number of students from other universities = 30% of 0.8X = 0.24 X

Ratio of students from other universities in different streams is

Physical Science = 0.024X, Arts = 0.072X, Commerce = 0.096X, computer = 0.048X

Given that number of students in arts stream = 780

Therefore,

0.072X+ 0.24X = 780

X= 2500

Hence, total number of students in first year = 2500

Total students in promoted to second year = 2000

Students from other Universities joining Chennai Anna University = 0.24X = 600

Total students studying in Chennai Anna University in second year = 2000+ 600 = 2600

Total science students in Chennai Anna University = 0.16x+0.024x = 460

First year pass- outs of Chennai Anna University joining science stream = 0.16X = 400

Required % = (400/460)×100=87%

18. (c)

Let us assume the total number of first year students in Chennai Anna university be X

Then, as per data, number of students who passed in first year = 0.8X

Students in science, commerce, arts and computer stream becomes: 0.16X, 0.32X, 0.24X, 0.08X respectively.

Total number of students from other universities = 30% of 0.8X = 0.24 X

Ratio of students from other universities in different streams is

Science = 0.024X, Arts = 0.072X, Commerce = 0.096X, computer = 0.048X

Given that number of students in arts stream = 780

Therefore,

0.072X+ 0.24X = 780

X= 2500

Hence, total number of students in first year = 2500

Total students in Anna University promoted to second year = 2000

19. (b)

Let us assume the total number of first year students in Chennai Anna university be X

Then, as per data, number of students who passed in first year = 0.7X

Students in Physical science, commerce, arts and computer stream becomes: 0.16X, 0.32X, 0.24X, 0.08X respectively.

Total number of students from other universities = 30% of 0.8X = 0.24 X

Ratio of students from other universities in different streams is

Physical Science = 0.024X, Arts = 0.072X, Commerce = 0.096X, computer = 0.048X

Given that number of students in arts stream = 780

Therefore,

0.072X+ 0.24X = 780

X= 2500

Hence, total number of students in first year = 2500

Total students in promoted to second year = 2000

Students from other Universities joining Chennai Anna University = 0.24X = 600

Total students studying in Chennai Anna University in second year = 2000+ 600 = 2600

20. (a)

Let us assume the total number of first year students in Chennai Anna university be X

Then, as per data, number of students who passed in first year = 0.8X

Students in Physical science, commerce, arts and computer stream becomes: 0.16X, 0.32X, 0.24X, 0.08X respectively.

Total number of students from other universities = 30% of 0.8X = 0.24 X

Ratio of students from other universities in different streams is

Physical Science = 0.024X, Arts = 0.072X, Commerce = 0.096X, computer = 0.048X

Given that number of students in arts stream = 780

Therefore,

0.072X+ 0.24X = 780

X= 2500

Hence, total number of students in first year = 2500

Total students in Anna University promoted to second year = 2000

Students from other Universities joining Chennai Anna University = 0.24X = 600

Total students studying in Chennai Anna University in second year = 2000+ 600 = 2600

Total number of students in commerce stream in 2015 = 0.32X+0.096X = 0.416X = 1040

21. ( b )

Let us assume the total number of first year students in Chennai Anna university be X

Then, as per data, number of students who passed in first year = 0.8X

Students in science, commerce, arts and computer stream becomes: 0.16X, 0.32X, 0.24X, 0.08X respectively.

Total number of students from other universities = 30% of 0.8X = 0.24 X

Ratio of students from other universities in different streams is

Science = 0.024X, Arts = 0.072X, Commerce = 0.096X, computer = 0.024X

Given that number of students in arts stream = 780

Therefore,

0.072X+ 0.24X = 780

X= 2500

Hence, total number of students in first year = 2500

Total students in promoted to second year = 2000

Students from other Universities joining Chennai Anna University = 0.24X = 600

Total students studying in Chennai Anna University in second year = 2000+ 600 = 2600