Target SBI PO : APTITUDE MOCK TEST DAY – 7
Directions (Q.1-5): What should come in place of the question mark (?) in the following questions?
1) 48% of 525 +? % of 350 = 374.5
(a) 35
(b) 45
(c) 57
(d) 47
(e) None of these
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a)
48/100 × 525 +x/100 × 350 = 374.5
252+3.5x=374.5
3.5x=122.5
2) 25.6% of 250 + = 128
(a) 4356
(b) 4096
(c) 3136
(d) 2916
(e) None of these
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b)
25.6/100 × 250 + √x = 128
64+ √x =128
√x=64
X =4096
3) 47% of ? +28% of 650 =? % of 73
(a) 600
(b) 700
(c) 800
(d) 900
(e) None of these
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b)
47/100 × x +28/100 × 650 =x/100 × 73
0.47x+182=0.73x
182=0.73x-0.47x
0.26x=182
X = 700
4) (21% of 1326) – (17% of 932)=?
(a) 120.02
(b) 206.05
(c) 240.04
(d) 120.20
(e) 122.22
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a)
(21/100 × 1326)– (17/100 × 932) =x
1/100 [27846-15844]= 120.02
X =120.02
5) 3.5% of 2400 +4.5% of 3200=1140?
(a) 2
(b) 3
(c) 4
(d) 5
(e) 6
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d)
3.5/100× 2400 +4.5/100× 3200=1140/x
3.5 ×24+4.5×32= 1140/x
84+144= 1140/x
x=1140/228=5
Directions (Q.6-10): What approximate value should come in place of the question mark (?) in the following questions?
6) (3/4+5/8+8/16-1/16)×2.432 =?
(a) 5
(b) 6
(c) 4.5
(d) 4.4
(e) 7.5
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d)
(3/4+5/8+8/16-1/16)×2.432 =?
29/16×2.4=?
x=4.35≈4.4
7) 79% of 3770 67% of 553 =?
(a) 6
(b) 7
(c) 9
(d) 8.5
(e) 8
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8) ((1.1×1.1)+(2.2×2.2)+(3.3×3.3))/(3.3+2.2+1.1)=?
(a) 1.2
(b) 2.5
(c) 5.2
(d) 3.8
(e) 4.6
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b)
((1.1×1.1)+(2.2×2.2)+(3.3×3.3))/(3.3+2.2+1.1)=?
(1.1(1.1+4.4+9.9))/6.6
(1.1+4.4+9.9)/6=?
15.4/6=2.566
9) (333 % of 856)49.95 =?
(a) 155000
(b) 141500
(c) 142500
(d) 142000
(e) 140000
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c)
(333 % of 856)49.95 =?
2850×50=142500
10) 196.1 x 196.1 x 196.1 x 4.01 x 4.01 x 4.001 x 4.999 x 4.999 =196.13 x 4.012 x ?
(a) 100
(b) 16
(c) 10
(d) 64
(e) 32
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a)
196.1 x 196.1 x 196.1 x 4.01 x 4.01 x 4.001 x 4.999 x 4.999 =196.13 x 4.012 x ?
=>〖(196.1)3×〖(4.01)3×(〖4.999)2=(196.1)3×(4.01)2×?
(〖(196.1)3×〖(4.01)3×(〖4.999)]2)/((196.1)3×(4.01)2)=?
4.01×(〖4.999)〗2=100
Missing Numbers
11)
175 225 325 475 675 925
78 (v) (w) (x) (y) (z)
What comes in place of y?
a) 478
b) 578
c) 378
d) 828
e) None of these.
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b)
The series is, +50, +100, +150, +200, +250
78+50= 128; (v)
128+100= 228; (w)
228+150 = 378; (x)
378+200 = 578; (y)
578+250 = 828; (z)
12)
10 11 19 46 110 235
129 (v) (w) (x) (y) (z)
What comes in place of z?
a) 364
b) 229
c) 354
d) 344
e) None of these.
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c)
“The series is, , ” [+13,+23,+33,+ 43,+53 +63]
129+1= 130; (v)
130+8= 138; (w)
138+27 = 165; (x)
165+64 = 229; (y)
229+125 = 354; (z)
13)
6 18 42 78 126 186
339 (v) (w) (x) (y) (z)
What comes in place of x?
a) 411
b) 421
c) 459
d) 375
e) None of these.
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a)
The series is, +12, +24, +36, +48, +60
339+12= 351; (v)
351+24= 375; (w)
375+36 = 411; (x)
411+48 = 459; (y)
459+60 = 519; (z)
14)
268 251 217 166 98 13
500 (v) (w) (x) (y) (z)
What comes in place of x?
a) 411
b) 398
c) 298
d) 388
e) None of these.
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b)
The series is, -17, -34, -51, -68, -85
500-17= 483; (v)
483-34= 449; (w)
449-51= 398; (x)
398-68 = 330; (y)
330-85 = 245; (z)
15)
150 225 375 600 900 1275
25 (v) (w) (x) (y) (z)
What comes in place of y?
a) 340
b) 320
c) 449
d) 245
e) None of these.
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e)
The series is, +75, +150, +225, +300,+375
25+75= 100; (v)
100+150= 250; (w)
250+225=475; (x)
475+300=775; (y)
775+375=1150; (z)
Wrong Number Series
16) 96 98 202 618 2490
a) 202
b) 98
c) 618
d) 2490
e) 96
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d)
96×1+(1×2)=98
98×2+(2×3)=202
202×3+(3×4)=618
618×4+(4×5)=2492≠2490
17) 122 126 152 277 902
a) 126
b) 122
c) 277
d) 152
e) 902
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a)
122+51=127≠126
127+52=152
152+53=277
277+54=902
18) 176 308 464 644 856 1096
a) 308
b) 644
c) 464
d) 1096
e) 176
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b)
176+(11×12)=308
308+(12×13)=464
464+(13×14)=646≠644
646+(14×15)=856
856+(15×16)=1096
19) 184 142 122 110 106.5
a) 106.5
b) 142
c) 184
d) 122
e) 110
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e)
184/2+50=142
142/2+51=122
122/2+50=111≠110
111/2+51=106.5
20) 72 153 388 1503 9567
a) 153
b) 72
c) 1503
d) 9597
e) 388
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e)
72×2+91=153
153×2+92=387≠388
387×2+93=1503
1503×2+94=9567
D.21-25) In the following question two quantities are given Quantity 1 and quantity 2 By solving those quantities give corresponding answer.
21) Quantity 1:
The average height of 16 students in a class is 142 cm. If the height of the teacher is added the average increases by 1 cm. What is the height of the teacher ?
Quantity 2:
A spiral is made up of 13 successive semicircles, with centres alternately at A and B, starting with centre at A. The radii of semicircles thus developed are 0.5 cm, 1.0 cm, 1.5 cm, 2.0 cm and so on. What is the total length of the spiral
a) Quantity 1 ≥ Quantity 2
b) Quantity 1 = Quantity 2 (or) No relation
c) Quantity 1>Quantity 2
d) Quantity 1 ≤ Quantity 2
e) Quantity 1<Quantity 2
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c)
Quantity 1:
Given, average height of 16 students = 142 cm
Total height = 142 x 16 cm
and, if the height of the teacher is added the average, then
The average height of 16 students + Teacher = 143
Total height = 17 x 143 cm
Hence, Height of the teacher = (17 x 143) – (142 x 16) = 159 cm
Quantity 2:
Circumference of first semicircle =πr=0.5π
Circumference of first semicircle =πr=1π
Circumference of first semicircle =πr=1.5π
Number of semicircles=13
The length of the spiral=n/2 (2a+(n-1)d)
a=0.5π,d=0.5π
=13/2 (2×0.5π+(13-1)0.5π)
=13/2×7π
=13/2×7×22/7
=13×11=143cm
Hence Quantity I >Quantity II
22) Quantity 1:
In how many different ways the letters of the word BLOATING be arranged?
Quantity 2:
In how many different ways the letters of the word SOLITARY be arranged?
a) Quantity 1 ≥ Quantity 2
b) Quantity 1 = Quantity 2 (or) No relation
c) Quantity 1>Quantity 2
d) Quantity 1 ≤ Quantity 2
e) Quantity 1<Quantity 2
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b)
Explanation:
Quantity 1:
There are 8 letters in the given word BLOATING and none of the letters comes more than once.
The required number of ways = 8! = 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 = 40320
Quantity 2:
There are 8 letters in the given word SOLITARY and none of the letters comes more than once.
The required number of ways = 8! = 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 = 40320
23) Quantity 1:
Average score of Rahul, Manish & Suresh is 63. Rahul’s score is 15 less than Ajay and 10 more than Manish. If Ajay scored 30 marks more than the average score of Rahul, Manish & Suresh, what is the sum of Manish’s and Suresh’s scores?
Quantity 2:
400 persons working 9 hours per day complete 1/4th of the work in 10 days. The number of additional persons working 8 hours per day, required to complete the remaining work in 20 days?
a) Quantity 1 ≥ Quantity 2
b) Quantity 1 = Quantity 2 (or) No relation
c) Quantity 1>Quantity 2
d) Quantity 1 ≤ Quantity 2
e) Quantity 1<Quantity 2
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e)
Explanation:
Quantity 1:
Let the score of Ajay = x
then, Rahul’s score = x – 15
and, Manish’s score = x – 25
According to the question,
Ajay’s score = 63 + 30 = 93
Hence, Rahul’s score = 93 – 15 = 78
Manish’s score = 93 – 25 = 68
Total marks of Rahul, Manish & Suresh = 63 x 3 = 189
Then, Suresh’s score = 189 – (78 + 68) = 43
The sum of Manish’s and Suresh’s scores = 68 + 43 = 111
Quantity 2:
400 person complete 1/4th of the working 9×10 hours = 90 hours
= 400 person complete the work in 90 × 4 = 360 hours
=1 person completes the work in 360 × 400 hours
Let the number of persons completing the work in 20 days be x.
Remaining work to be done = 1 – 1/4 = 3/4
x person complete 3/(4 ) th of the work in 8×20 hours = 160 hours
= x person complete the work in 160×4/3 hours
= 1 person completes the work in 160×4/3×x hours
Time taken by 1 person to complete the work in both the cases will be same
So, 360 × 400 = 160×4/3×x
x = 675
So additional people required to complete the remaining work = 675 – 400 = 275
Hence Quantity I < Quantity II
24) Quantity 1:
A shopkeeper bought a bat and sold it at a loss of 15 %. If he had bought it for 20 % less and sold it for Rs. 147.2 more, he would have had profit of 35 %. What is the cost price of bat ?
Quantity 2:
A sells a bicycle to B at a profit of 20% and B sells it to C at a profit of 25%.If C pays Rs.225 for it, what did A pay for it.
a) Quantity 1 ≥ Quantity 2
b) Quantity 1 = Quantity 2 (or) No relation
c) Quantity 1>Quantity 2
d) Quantity 1 ≤ Quantity 2
e) Quantity 1<Quantity 2
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c)
Explanation:
Quantity 1:
Let cost price of bat is x.
Then S.P.=85x/100=17x/20.
If he had bought it for 20 % less:
C.P.=80x/100=4x/5
And, S.P. =17x/20+ 147.2 =(17x + 2944)/20
Now,
(S.P. –C.P.)/C.P× 100 = 35
[(17x + 2944)/20-4x/5]/((4x/5) )× 100 = 35
= (17x + 2944 – 16x)/(20 )×5/4x× 100 = 35
=(x + 2944)/20×125/x= 35
=(x + 2944)/4×25/x= 35
= 25x + 73600 = 140x
= x = 73600/115= 640
Cost price of Bat = Rs 640
Quantity 2:
C.P of A =225×100/(100+20)×100/(100+25)
=225×100/120×100/125=150
Rs.150
Hence Quantity 1>Quantity2
25) Quantity 1:
After working for 8 days .Anil finds that only of the work has been done.He employs Rakesh who is 60% efficient as Anil.How many more days will Anil take to complete the job
Quantity 2:
8 men and 4 women together can complete a piece of work in 6 days. Work done by a man in one day is double the work done by a woman in one day. If 8 men and 4 women started working and after 2 days, 4 men left and 4 new women joined, in how many more days will the work be completed ?
a) Quantity 1 ≥ Quantity 2
b) Quantity 1 = Quantity 2 (or) No relation
c) Quantity 1>Quantity 2
d) Quantity 1 ≤ Quantity 2
e) Quantity 1<Quantity 2
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c)
Explanation:
Quantity 1:
In 8 days Anil does=1/3 rd work
In 1 day=1/24 thwork
Rakesh’s one day work=60% of 1/24=1/40th work
Remaining work=1-1/3=2/3
Anil &Rakesh’s one day’s work
=1/24+1/40=1/15 th
2/3 rdwork=15×2/3=10 days
Quantity 2:
Work completed by 8M + 4W in 2 days = 2 ×1/6=1/3
Work done by 1 man = work done by 2 women
8 men + 4 women = (16 women + 4 women) = 20 women
8 men + 4 women = (8 men + 2 men) = 10 men
Work done by 20 women in 1 day = 1/20× 6 = 1/120
Work done by 10 men in 1 day =1/10× 6 = 1/60
As 4 men left and 4 new women joined, so 4M + 8W =
4×1/60+ 8 ×1/120=1/15+1/15=2/15
Work to be done 1 -1/3=2/3
No of days required (2/3)/(2/15)= 5 days.
