## Target SBI PO : APTITUDE MOCK TEST DAY – 7

Directions (Q.1-5): What should come in place of the question mark (?) in the following questions?

1) 48% of 525 +? % of 350 = 374.5

(a) 35

(b) 45

(c) 57

(d) 47

(e) None of these

Click Here To View Answer

a)

48/100  × 525 +x/100  × 350 = 374.5

252+3.5x=374.5

3.5x=122.5

2) 25.6% of 250 + = 128

(a) 4356

(b) 4096

(c) 3136

(d) 2916

(e) None of these

Click Here To View Answer

b)

25.6/100 × 250 + √x  = 128

64+ √x =128

√x=64

X =4096

3) 47% of ? +28% of 650 =? % of 73

(a) 600

(b) 700

(c) 800

(d) 900

(e) None of these

Click Here To View Answer

b)

47/100 × x +28/100  × 650 =x/100  × 73

0.47x+182=0.73x

182=0.73x-0.47x

0.26x=182

X = 700

4) (21% of 1326) – (17% of 932)=?

(a) 120.02

(b) 206.05

(c) 240.04

(d) 120.20

(e) 122.22

Click Here To View Answer

a)

(21/100 × 1326)– (17/100 × 932) =x

1/100 [27846-15844]= 120.02

X =120.02

5) 3.5% of 2400 +4.5% of 3200=1140?

(a) 2

(b) 3

(c) 4

(d) 5

(e) 6

Click Here To View Answer

d)

3.5/100× 2400 +4.5/100× 3200=1140/x

3.5 ×24+4.5×32= 1140/x

84+144= 1140/x

x=1140/228=5

Directions (Q.6-10): What approximate value should come in place of the question mark (?) in the following questions?

6) (3/4+5/8+8/16-1/16)×2.432 =?

(a) 5

(b) 6

(c) 4.5

(d) 4.4

(e) 7.5

Click Here To View Answer

d)

(3/4+5/8+8/16-1/16)×2.432 =?

29/16×2.4=?

x=4.35≈4.4

7) 79% of 3770 67% of 553 =?

(a) 6

(b) 7

(c) 9

(d) 8.5

(e) 8

Click Here To View Answer

e)

2978÷370=7.56≈8

8) ((1.1×1.1)+(2.2×2.2)+(3.3×3.3))/(3.3+2.2+1.1)=?

(a) 1.2

(b) 2.5

(c) 5.2

(d) 3.8

(e) 4.6

Click Here To View Answer

b)

((1.1×1.1)+(2.2×2.2)+(3.3×3.3))/(3.3+2.2+1.1)=?

(1.1(1.1+4.4+9.9))/6.6

(1.1+4.4+9.9)/6=?

15.4/6=2.566

9) (333 % of 856)49.95 =?

(a) 155000

(b) 141500

(c) 142500

(d) 142000

(e) 140000

Click Here To View Answer

c)

(333 % of 856)49.95 =?

2850×50=142500

10) 196.1 x 196.1 x 196.1 x 4.01 x 4.01 x 4.001 x 4.999 x 4.999 =196.13 x 4.012 x ?

(a) 100

(b) 16

(c) 10

(d) 64

(e) 32

Click Here To View Answer

a)

196.1 x 196.1 x 196.1 x 4.01 x 4.01 x 4.001 x 4.999 x 4.999 =196.13 x 4.012 x ?

=>〖(196.1)3×〖(4.01)3×(〖4.999)2=(196.1)3×(4.01)2×?

(〖(196.1)3×〖(4.01)3×(〖4.999)]2)/((196.1)3×(4.01)2)=?

4.01×(〖4.999)〗2=100

Missing Numbers

11)

175         225         325         475         675         925

78           (v)          (w)         (x)          (y)          (z)

What comes in place of y?

a) 478

b) 578

c) 378

d) 828

e) None of these.

Click Here To View Answer

b)

The series is, +50, +100, +150, +200, +250

78+50= 128; (v)

128+100= 228; (w)

228+150 = 378; (x)

378+200 = 578; (y)

578+250 = 828; (z)

12)

10          11           19           46           110         235

129         (v)          (w)         (x)          (y)          (z)

What comes in place of z?

a) 364

b) 229

c) 354

d) 344

e) None of these.

Click Here To View Answer

c)

“The series is, , ” [+13,+23,+33,+ 43,+53 +63]

129+1= 130; (v)

130+8= 138; (w)

138+27 = 165; (x)

165+64 = 229; (y)

229+125 = 354; (z)

13)

6            18           42           78           126         186

339         (v)          (w)         (x)          (y)          (z)

What comes in place of x?

a) 411

b) 421

c) 459

d) 375

e) None of these.

Click Here To View Answer

a)

The series is, +12, +24, +36, +48, +60

339+12= 351; (v)

351+24= 375; (w)

375+36 = 411; (x)

411+48 = 459; (y)

459+60 = 519; (z)

14)

268        251         217         166         98           13

500         (v)          (w)         (x)          (y)          (z)

What comes in place of x?

a) 411

b) 398

c) 298

d) 388

e) None of these.

Click Here To View Answer

b)

The series is, -17, -34, -51, -68, -85

500-17= 483; (v)

483-34= 449; (w)

449-51= 398; (x)

398-68 = 330; (y)

330-85 = 245; (z)

15)

150        225         375         600         900         1275

25           (v)          (w)         (x)          (y)          (z)

What comes in place of y?

a) 340

b) 320

c) 449

d) 245

e) None of these.

Click Here To View Answer

e)

The series is, +75, +150, +225, +300,+375

25+75= 100; (v)

100+150= 250; (w)

250+225=475; (x)

475+300=775; (y)

775+375=1150; (z)

Wrong Number Series

16) 96     98      202    618    2490

a) 202

b) 98

c) 618

d) 2490

e) 96

Click Here To View Answer

d)

96×1+(1×2)=98

98×2+(2×3)=202

202×3+(3×4)=618

618×4+(4×5)=2492≠2490

17) 122   126    152    277    902

a) 126

b) 122

c) 277

d) 152

e) 902

Click Here To View Answer

a)

122+51=127≠126

127+52=152

152+53=277

277+54=902

18) 176   308    464    644    856    1096

a) 308

b) 644

c) 464

d) 1096

e) 176

Click Here To View Answer

b)

176+(11×12)=308

308+(12×13)=464

464+(13×14)=646≠644

646+(14×15)=856

856+(15×16)=1096

19) 184   142    122    110    106.5

a) 106.5

b) 142

c) 184

d) 122

e) 110

Click Here To View Answer

e)

184/2+50=142

142/2+51=122

122/2+50=111≠110

111/2+51=106.5

20) 72     153    388    1503  9567

a) 153

b) 72

c) 1503

d) 9597

e) 388

Click Here To View Answer

e)

72×2+91=153

153×2+92=387≠388

387×2+93=1503

1503×2+94=9567

D.21-25) In the following question two quantities are given Quantity 1 and quantity 2 By solving those quantities give corresponding answer.

21) Quantity 1:

The average height of 16 students in a class is 142 cm. If the height of the teacher is added the average increases by 1 cm. What is the height of the teacher ?

Quantity 2:

A spiral is made up of 13 successive semicircles, with centres alternately at A and B, starting with centre at A. The radii of semicircles thus developed are 0.5 cm, 1.0 cm, 1.5 cm, 2.0 cm and so on. What is the total length of the spiral

a) Quantity 1 ≥ Quantity 2

b) Quantity 1 = Quantity 2 (or) No relation

c) Quantity 1>Quantity 2

d) Quantity 1 ≤ Quantity 2

e) Quantity 1<Quantity 2

Click Here To View Answer

c)

Quantity 1:

Given, average height of 16 students = 142 cm

Total height = 142 x 16 cm

and, if the height of the teacher is added the average, then

The average height of 16 students + Teacher = 143

Total height = 17 x 143 cm

Hence, Height of the teacher = (17 x 143) – (142 x 16) = 159 cm

Quantity 2:

Circumference of first semicircle =πr=0.5π

Circumference of first semicircle =πr=1π

Circumference of first semicircle =πr=1.5π

Number of semicircles=13

The length of the spiral=n/2 (2a+(n-1)d)

a=0.5π,d=0.5π

=13/2 (2×0.5π+(13-1)0.5π)

=13/2×7π

=13/2×7×22/7

=13×11=143cm

Hence Quantity I >Quantity II

22) Quantity 1:

In how many different ways the letters of the word BLOATING be arranged?

Quantity 2:

In how many different ways the letters of the word SOLITARY be arranged?

a) Quantity 1 ≥ Quantity 2

b) Quantity 1 = Quantity 2 (or) No relation

c) Quantity 1>Quantity 2

d) Quantity 1 ≤ Quantity 2

e) Quantity 1<Quantity 2

Click Here To View Answer

b)

Explanation:

Quantity 1:

There are 8 letters in the given word BLOATING and none of the letters comes more than once.

The required number of ways = 8! = 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 = 40320

Quantity 2:

There are 8 letters in the given word SOLITARY and none of the letters comes more than once.

The required number of ways = 8! = 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 = 40320

23) Quantity 1:

Average score of Rahul, Manish & Suresh is 63. Rahul’s score is 15 less than Ajay and 10 more than Manish. If Ajay scored 30 marks more than the average score of Rahul, Manish & Suresh, what is the sum of Manish’s and Suresh’s scores?

Quantity 2:

400 persons working 9 hours per day complete 1/4th of the work in 10 days. The number of additional persons working 8 hours per day, required to complete the remaining work in 20 days?

a) Quantity 1 ≥ Quantity 2

b) Quantity 1 = Quantity 2 (or) No relation

c) Quantity 1>Quantity 2

d) Quantity 1 ≤ Quantity 2

e) Quantity 1<Quantity 2

Click Here To View Answer

e)

Explanation:

Quantity 1:

Let the score of Ajay = x

then, Rahul’s score = x – 15

and, Manish’s score = x – 25

According to the question,

Ajay’s score = 63 + 30 = 93

Hence, Rahul’s score = 93 – 15 = 78

Manish’s score = 93 – 25 = 68

Total marks of Rahul, Manish & Suresh = 63 x 3 = 189

Then, Suresh’s score = 189 – (78 + 68) = 43

The sum of Manish’s and Suresh’s scores = 68 + 43 = 111

Quantity 2:

400 person complete 1/4th of the working 9×10 hours = 90 hours

= 400 person complete the work in 90 × 4 = 360 hours

=1 person completes the work in 360 × 400 hours

Let the number of persons completing the work in 20 days be x.

Remaining work to be done = 1 – 1/4 = 3/4

x person complete 3/(4  ) th of the work in 8×20 hours = 160 hours

= x person complete the work in 160×4/3 hours

= 1 person completes the work in 160×4/3×x hours

Time taken by 1 person to complete the work in both the cases will be same

So, 360 × 400 = 160×4/3×x

x = 675

So additional people required to complete the remaining work = 675 – 400 = 275

Hence Quantity I < Quantity II

24) Quantity 1:

A shopkeeper bought a bat and sold it at a loss of 15 %. If he had bought it for 20 % less and sold it for Rs. 147.2 more, he would have had profit of 35 %. What is the cost price of bat ?

Quantity 2:

A sells a bicycle to B at a profit of 20% and B sells it to C at a profit of 25%.If C pays Rs.225 for it, what did A pay for it.

a) Quantity 1 ≥ Quantity 2

b) Quantity 1 = Quantity 2 (or) No relation

c) Quantity 1>Quantity 2

d) Quantity 1 ≤ Quantity 2

e) Quantity 1<Quantity 2

Click Here To View Answer

c)

Explanation:

Quantity 1:

Let cost price of bat is x.

Then S.P.=85x/100=17x/20.

If he had bought it for 20 % less:

C.P.=80x/100=4x/5

And, S.P. =17x/20+ 147.2 =(17x + 2944)/20

Now,

(S.P. –C.P.)/C.P× 100 = 35

[(17x + 2944)/20-4x/5]/((4x/5) )× 100 = 35

= (17x + 2944 – 16x)/(20 )×5/4x× 100 = 35

=(x + 2944)/20×125/x= 35

=(x + 2944)/4×25/x= 35

= 25x + 73600 = 140x

= x = 73600/115= 640

Cost price of Bat = Rs 640

Quantity 2:

C.P of A =225×100/(100+20)×100/(100+25)

=225×100/120×100/125=150

Rs.150

Hence Quantity 1>Quantity2

25) Quantity 1:

After working for 8 days .Anil finds that only of the work has been done.He employs Rakesh  who is 60% efficient as Anil.How many more days will Anil take to complete the job

Quantity 2:

8 men and 4 women together can complete a piece of work in 6 days. Work done by a man in one day is double the work done by a woman in one day. If 8 men and 4 women started working and after 2 days, 4 men left and 4 new women joined, in how many more days will the work be completed ?

a) Quantity 1 ≥ Quantity 2

b) Quantity 1 = Quantity 2 (or) No relation

c) Quantity 1>Quantity 2

d) Quantity 1 ≤ Quantity 2

e) Quantity 1<Quantity 2

Click Here To View Answer

c)

Explanation:

Quantity 1:

In 8 days Anil does=1/3 rd work

In 1 day=1/24 thwork

Rakesh’s one day work=60% of 1/24=1/40th work

Remaining work=1-1/3=2/3

Anil &Rakesh’s one day’s work

=1/24+1/40=1/15 th

2/3 rdwork=15×2/3=10 days

Quantity 2:

Work completed by 8M + 4W in 2 days = 2 ×1/6=1/3

Work done by 1 man = work done by 2 women

8 men + 4 women = (16 women + 4 women) = 20 women

8 men + 4 women = (8 men + 2 men) = 10 men

Work done by 20 women in 1 day = 1/20× 6 = 1/120

Work done by 10 men in 1 day =1/10× 6 = 1/60

As 4 men left and 4 new women joined, so 4M + 8W =

4×1/60+ 8 ×1/120=1/15+1/15=2/15

Work to be done  1 -1/3=2/3

No of days required (2/3)/(2/15)= 5 days.