BLUE WHALE CHALLENGE QUESTIONS

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IBPS RRB , Bank of Baroda PO and RBI Grade “B” Exams are the upcoming exams and students need to get ready for the battle. Always aspirants find it difficult to attend the miscellaneous questions in particular and also the Puzzle and Seating Arrangement Questions in common.

So we will be providing BLUE WHALE CHALLENGE Questions Daily which is a combination of 4-5 topics and note that only one question will be provided daily. The BLUE WHALE CHALLENGE Questions will be updated daily @ 9:00 P.M regularly and the answers for the same will be posted @ 9:00 P.M the next day.



Please comment the answers for the BLUE WHALE CHALLENGE Questions in the below given format. 


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Questions of DAY 11 UPDATED now. Answer for the BLUE WHALE CHALLENGE now and mention the Answers in the Comments. 


Day 11 Question

Q.1) The profit earned on a laptop is 3/4th of the profit earned on a watch. A shopkeeper sells the laptop and watch at Rs.3500 each. The cost price of the watch is Rs.200 more than the cost price of the laptop. The profit earned on the watch is numerically equal to four times of the length of a train (in m). The train crosses a boat in 20 seconds. The boat moves (downstream) in the same direction as train (The length of boat is negligible). The speed of the train is 1.5 times the speed of the boat in downstream. The upstream speed of the boat is ‘z’ km/hr. The total time taken by boat to cover downstream distance and upstream distance is 6 hours. (downstream distance = upstream distance) The number of five digit odd numbers that can be formed from 0,1,5,6,7,9 and 3 (Repetion allowed) is numerically equal to the number of students studying in the RACE Chennai branch. The percentage of female students studying in RACE Chennai branch is (z+4)%. The number of male students studying in the RACE Chennai branch is 6174. The distance covered by the boat is numerically 100 more than the circumference of a circle (in m). The area of the circle is numerically equal to the interest (in Rs.) received by john from bank A which gives interest rate of 30% per annum @S.I instead of 22% per annum he received Rs.210. The sum deposited by john in bank A is numerically equal to the total number of persons working in a company. The average salary of male and female who are working in the company is Rs.14000 and Rs.7000 respectively. The average salary of the total number of persons working in the company is Rs.10000. Find the number of males working the company.

a) 200

b) 400

c) 300

d) 100

e) 500


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Q.1) c

Let profit earned on the laptop and watch be Rs. 3/4x and Rs.x respectively

(3500 – 3/4x) – (3500 – x)= 200

X= 800

Therefore the length of the train is 

Let the speed of boat in downstream and the speed of train be x m/s and 1.5x m/s

2001.5x-x=20

0.5X = 10 m/sec => 36 km/hr

X = 72 km/hr

Speed of boat in downstream is 72 km/hr

Required number of ways to form five digit odd numbers =6×7×7×7×5=10290

Female students studying in the RACE institute = 10290 – 6174 = 4116

Z = 36

Therefore the speed of boat in upstream is 36 km/hr

D = 144

Therefore the circumference of the circle = 144-100= 44 m

R = 44×(7/22)X(1/2)

R = 7

The area of the circle = (22/7)×7×7=154

The interest received by john from bank A which offers 22% per annum is Rs.154

The interest received by john from bank A which offers 30% per annum is Rs.210

Let sum be Rs.x

30% of x – 22% of x = 210- 154

8% of x = 56

X = 700

Therefore the number of persons working in the company is 700

Let the number of males and females be x and 700-x respectively

X = 300


Day 10 Questions 

Q.1) 24 men can complete  3/4th of a work in 12 days and 33 women can complete 60% of the work in 30 days. The number of days required by 32 men and 25 women to complete the entire work is x/13 days. The total age of vijay, ajith, surya and vijay sethupathi is x years. The age of ajith 14 years ago is 3 times the present age of vijay sethupathi. The age of vijay 22 years hence is 2 times the present age of Surya. 4 years hence, the sum of the age of Surya and that of vijay sethupathi is numerically equal to the quantity of milk (in litres) in a jar. A person drawn y litres of milk from the jar and replaces it with water. He then repeated the same process one more time, resulting in 32 litres of milk In the jar. Train 1 which is of length 200 m crosses a pole in y seconds. It then crosses train 2 which is length of 300m moving in opposite direction in  y seconds. The speed of train 2 (in km/hr) is numerically equal to the difference between the perimeter of the square and the perimeter of the rectangle. The area of the square is 256 m². The length of the rectangle is 22 m more than the breadth of the rectangle. The breadth of the rectangle is numerically equal to twice the difference between the S.I and C.I (in. Rs) for 2 years at 8% per annum. Find the principal.

a) Rs.7500

b) Rs.10000

c) Rs.15000

d) Rs.20000

e) Rs.5000


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Q.1) b

Man’s per day work =

Woman’s per day work

32men + 25 women’s per day work

Therefore the value of x = 132

The total age of vijay, ajith, surya and vijay sethupathi is 132 years.

Ajith – 14= 3 Vijay sethupathi

Vijay + 22 = 2 surya

Ajith – 22 = vijay

Ajith = vijay +22

Surya = 

3Vijay sethupathi-8 =Ajith-14-8

3 Vijay sethupathi-8= vijay

Vijay sethupathi= 

 

Vijay = 34 years

Vijay sethupathi = 14 years

Surya = 28 years

Quantity of milk = 28+ 14+ 8 = 50 litres

32

Y = 10

Speed of train 1 = 200/10=20m/s

Let Speed of train 2 be a m/s

a= 30 m/s => 108 km/hr

side of the square = √256=16 m

perimeter of the square is 64

Perimeter of the rectangle – perimeter of the square = 108

Perimeter of the rectangle is 172

2 (l+b) = 174

L+ b= 86

L – b= 22

2l = 54

L = 54 m

B = 32 m

Diff =

64 =

P = Rs.10000


Day 9 Questions 

Q.1) There are two trains first train crosses a 100m platform in 4t seconds and speed of the train is 25m/s. second train crosses a standing man with speed of 30 m/s in t seconds. If the length of first train is 100% more than the second train. Sum of the length of two train is numerically equal to area of a square (in m²). The side of the square is numerically equal to average of five consecutive odd numbers. The product of smallest and highest number is equal to the number of the students of a school. The difference between the boys and girls in the school is equal to sum of 10 natural numbers. Which of the following is the ratio of boys to girls? (Boys are more than girls)

a)14:5

b) 12:7

c) 3:4

d) 13:12

e) 16:23


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Q.1) b

Length of second train = 30t

Length of first train = 60t

100+60t = 100t

100 = 40t

T = 2.5

Sum of the length of first train and second train = 90t = 90 ×2.5=225

Side of a square =  

The numbers are 11,13,15,17,19

Product of largest and smallest number = 11 ×19=209

sum of ten natural numbers = 

let boys are more than girls

boys+girls = 209

boys-girls = 55

boys = 132

girls = 77

Their ratio = 132:77 = 12:7


Day 8 Questions 

Q.1) A, B, C, D, E and F are sitting in a circle. Two persons are facing the center and the remaining persons are facing away from the center. Each person has different number of chocolates 40, 60, 80, 100, 120 and 140 but not necessarily in the same order. F sits between B and C. E is not an immediate neighbour of B and C. E has 140 chocolates. The number of persons sits between the one who has 120 chocolates and the one who has 100 chocolates is same as between the one who has 80 chocolates and the one who has 140 chocolates. The one who has 80 chocolates and E are facing each other. The one who has 100 chocolates sits to the immediate right of F. D has 40 chocolates. C has second minimum number of chocolates. The one who sits second to the left of B and the one who sits fourth to the left of A have the total number of chocolates which is numerically equal to the interest (in. Rs) received by Arun in bank B. The one who sits third to the left of D and the one who sits fourth to the left of C have the number of chocolates which is numerically equal to the interest (In.Rs) received by Hari in bank A. Arun invested Rs.x at 5% per annum S.I in bank B. Hari invested Rs.(2x + 400) at 2.5% per annum S.I in bank A. Hari and Arun invested their amount for same period in respective banks. The amount invested by Hari is numerically equal to the cost price of the laptop. A shopkeeper sold the laptop at Rs.5000. The profit percentage of laptop is numerically equal to the number of days taken by Selva to complete a piece of work. Arul can complete the same work in y days. Arul and Selva can complete the same work in days. A bag contains 20 blue balls, 30 yellow balls and y black balls. If two balls are drawn at random, what is the probability that two balls are black?

a)

b)

c)

d)

e)


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BWC - Day 8

The interest received by arun in bank B = 100 + 80 = Rs.180

The interest received by hari in bank A = 60 + 140 = Rs.200

From the question,

X = Rs.1800

Therefore, the amount invested by hari is Rs. 4000

Profit % = 

Arul + selva’ s one day work = (3 / 50)

(1 / y)+ (1 / 25) = (3/50)

Y= 50

Required probability =BWC - Day 8 - Pro

 


Day 7 Questions 

Q.1) In the question, a number is followed by five arithmetic problems, you can solve all arithmetic problems and choose the option whose answer is numerically not equal to that number 

100

I. The difference between the distance covered by a car travels with its normal speed in 4 hours and the distance covered by a car travels with its half of normal speed in 6 hours is 40 km. How much distance travelled by the car in 2.5 hours.

II. The Ratio between the Profit earned on a product and the discount of the product is 2: 3. The difference between the Cost price and marked price is Rs.200. If profit percentage of the product is 80%, find the cost price of the product.

III. The present age of B is equal to the age of A 30 years ago. The present age of C is equal to the age of B 35 years ago. Some of the present age of A, B and C is 2.05 times of the present age of A. Find the present age of A.

IV. The average salary of male workers in a company is Rs.200x and the average salary of female workers in the company is Rs.150x. The average salary of the workers in the company is Rs.170x. The number of male workers in the company is 20. Find the total number of workers in the company.

V. How many 3 digit even numbers can be formed from 4,6, 8, 2 and 0?

a) I, III, IV and II

b) I, II and III

c) None

d) All I, II, III, IV and V

e) I, II, IV and V


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Q.1) c

I.

Let speed of the car is x km/hr

x×4-x2×6=40

X = 40

Required distance =40×2.5=100 km

II

Cost price – marked price = Profit + Discount

200 = Profit + Discount

200 = 2x + 3x

X = 40

Profit = Rs.80

The cost price = 8080×100=Rs.100

III.

Let the present age of A is x years

From the question,

X + x – 30 + x -30 -35 = 2.05 x

X = 100

IV.

BLUE WHALE CHALLENGE QUESTIONS – Day 8

Ratio between the male and female workers is = 2: 3

Required total = 402×5=100

V.

Required ways = 4× 5×5 = 100 numbers

 


Day 1 Questions 

Q1. The Speed of a boat (kmph) in still water is numerically equal to 1 / 4th of perimeter of a circle whose radius is 7 m. The speed of the stream is x kmph. An average age of a family is x years. Which consist of four persons and their ratio of ages are 2:3:4:5. The 2nd youngest person age is 6 years. The distance traveled by the boat through downstream in 5 hours is numerically equal to selling price (in Rs) of an item. If the seller face loss of 10% what is the cost price of the item?

a) Rs.200

b) Rs.150

c) Rs.100

d) Rs.250

e) Rs.175


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Q.1) c

Perimeter of the circle = 2πr² ×(22/7) ×7=44cm

Speed of the boat in still water = 14 ×44=11 kmph

Average age of family = x

Ratio of the ages of family = 2x:3x:4x:5x

2nd youngest person age = 3x = 6; x=2

Average age of the family = (1/4) x 4=(28/4)=7

Speed of the stream = 7kmph

The downstream of the boat = 11+7 = 18kmph

Distance travelled by boat in 5 hours = 18 × 5=90km

Selling price of an item = Rs 90

Cost price = 90 ×(100/90)=Rs 100


Day 2 Questions 

Q.1) A man go to his office from his home at 5kmph more than normal speed he will reach office in 20 minutes earlier. If he goes to his office at 10km/hr less than normal speed he will reach office 80 minutes later. The time taken to cover the distance with normal speed is equal to time taken by a tap to fill a tank. The tap fills 30 litres per minute. The capacity of the tank is x litres. An area of a square is x m2. Perimeter of the square is numerically equal to average of five consecutive even numbers. Find the difference between the smallest number and cube of 6.

a) 15

b) 25

c) 10

d) 20

e) None of these

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Q.1) d

Let distance and original speed of the man be ‘d’ km and ‘s’ km/hr respectively

Blue Whale Challenge Questions - 10th July

Blue Whale Challenge - BankersdailyOn solving above two equation we get,

d= 50 and s = 25

Time taken with normal speed = Blue Whale Challenge - Bankersdaily

Tank filled by tap in 2 hours

Capacity of tank =30×120=3600 litres

Area of the square = 3600 m2

Side of the square = 60 m

Perimeter of the square = 4a =4×60=240m

Five consecutive even numbers are x, x+2, x+4, x+6 and x+8

Sum of numbers =240×5=1200

5x + 20 = 1200

X = 236

Required difference =Blue Whale Challenge - Bankersdaily


Q.2) The speed of a boat in downstream and upstream is 40km/hr and 2x km/hr respectively. The speed of the stream is x km/hr. A, B and C can do a piece of work in x, 2x and 3x days respectively. Initially, the least efficient person worked for 3 days and then left. Then B worked for 4 days and left. The remaining work was completed by the most efficient person in y days. A shopkeeper mixes x kg of variety 1 rice cost of Rs.3y/kg with y kg of variety 2 rice cost of Rs.2x/kg , sold the mixture at a price of Rs.z/kg and he did not get any profit. The cost price of a product is Rs.34z and gains x% when offers discount of 23%. Selva invests Rs.510z at simple interest of x% per annum for 4 years in bank A and then he withdraw all the money from bank A to invest in bank B which offers compounded half yearly of x% per annum for 1 year. Find the difference between the interest received from bank A and B together and the marked price of the product.

a) Rs.5706.25

b) Rs.7060.75

c) Rs.4706.75

d) Rs.6406.75

e) Rs.6555.75

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Q.2) c

Speed of the stream,

(40- 2x) = x

X = 10 km/hr

A, B and C can do the work in 10, 20 and 30 days.

Total units = 60 (LCM of 10, 20 and 30)

A = 6 units/day

B = 3 units/day

C = 2 units/day

Least efficient person is C worked for  3 days then 3× 2 = 6 units completed

B worked for 4 days then 4 × 3 = 12 units completed

Remaining 42 units completed by A in (42/6)=7 days

Y = 7 days

Blue Whale Challenge - Bankersdaily

Blue Whale Challenge - Bankersdaily

Z = 350/17

The cost price of the product = 34×(350/17)=Rs.700

Marked price = 700×(110/100)X (100/77) =Rs.1000

Principle is 510×(350/17) =Rs.1050

Bank A,

10500×4×(10/100)=Rs.4200

Bank B,

(10500+4200) ((1+(5/100))²-14700=1506.75

Required difference = (4200+ 1506.75) – 1000 = Rs.4706.75


DAY 3 QUESTIONS 

Q.1) There are four persons A, B, C and D are sitting in a row. All are facing north. All of them has different ages 20yrs, 25yrs, 30yrs and 35yrs, but not necessarily in the same order. The number of persons sits between A and B is same as between C and D. A is not an immediate neighbour of B and D. The age of A is 30 yrs. The sum of the age of B and C is numerically same as the number of days taken by Arul to complete a piece of work. Arul and Bala together can complete the same work in 20 days. Bala can complete the same work in x days. 70% of its usual speed, a train of length 10x m crosses a platform of length 190m in 7 seconds. At its normal speed, the train crosses a pole in 3 seconds.  The age of one who sits third to the right of A is z years. How many different straight lines can be formed by joining ‘z’ different points on a plane of which 4 are collinear and the rest are non-collinear?

a) 184

b) 190

c) 185

d) 181

e) 180

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Q.1) c

Usual speed of the train be S km/hr

70% of S =Blue Whale Challenge - Day 3 - Bankersdaily

S =(10x / 3)

70% of (10x / 3)Blue Whale Challenge - Day 3 - Bankersdaily

X = 30

Therefore, Bala can complete the work in 30 days.

Arul’s per day work = Blue Whale Challenge - Day 3 - Bankersdaily

Therefore, Arul can complete the work in 60 days.

Hence, the sum of the ages of B and C is 60 years.

Therefore, we can find the age of D is 20 years because age of A is 30 years remaining given age is 25 years, 30 years and 35years out of three the sum of the two is 60 years so that should be 25 years and 35 years.

Blue Whale Challenge - Day 3 - Bankersdaily

Hence value of z is 20

Straight line can be formed by joining 2 points

Total number of lines formed by 20 points = 

Number of lines formed by 4 points = 4

But it also includes that in which 4 points are in straight line. From those 4 points only one line can be formed.

Required number of lines = 


DAY 4 QUESTIONS 

Q.1) Aryan can do a piece of work in 16 days. Due to some problem, his efficiency reduces to 40%. Ankur’s efficiency also reduces to two-third of his original efficiency. Now they can finish the work together in 20 days. The number of days can Ankur and Aryan together finish the work at 100% efficiency is numerically equal to the length (in m) of the rectangle. Distance travelled by train whose speed is 72km/hr in  seconds is equal to perimeter of the rectangle. Find the area of the rectangle?

 

a) 75

b) 100

c) 50

d) 88

e) 112


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Q.1) c

When efficiency is 100% Aryan can finish the work in 16 days

When efficiency is 40% then, ( (16×100) ÷ (40) )=40 days

Ankur’s efficiency is two- third and they can finish the work in 20 days.

So, Ankur’s 1 day work ((1÷20) – (1÷40)) = (1÷40)

So, Ankur can finish the work in 40 days when efficiency is two-third.

So, When efficiency is 100% Ankur can finish the work in = ( (40×2) ÷ 3 )= (80 ÷ 3) days.

One day work by both of them when working at 100% efficiency = ( (1÷16) + (3÷80)) = (1÷10)

Total time taken to complete the work=10days.

Length of the rectangle = 10 m

30= 2(L+B) …………………………….II

Solve I & II, we get

L = 10m ; B = 5m

Area of the rectangle = L×B=10×5=50


DAY 5 Questions

Q.1) 700, 720, 820, 1020, 1340, ___ , the number missing in the given number series is numerically equal to the amount invested by sarkar in bank A. x²-7x-450=0 the positive value of x is numerically equal to the rate of interest per annum(@ S.I) given by Bank A.

35% of 4580 – 48 ×72 + 93× 97 = y + 4168 the value of y is numerically equal to the amount invested by viswasam in bank B which gives 30% rate of interest per annum at simple interest. The difference between the interest received by Sarkar and the interest received by viswasam is Rs.1800.

Find the number of years at which the amount invested by viswasam in bank B, If the sum of the years invested by Sarkar and viswasam is 5 years. (Note Interest received by Sarkar < interest received by viswasam)

a) 3 years

b) 2 years

c) 4 years

d) 1 years

e) 5 years


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Q.1) a

The difference is,

The missing number is 1800

Therefore, Sarkar invested Rs.1800 in bank A.

X = 25 , -18

The rate of interest given by bank A is 25%

1603 – 3456 + 9021 = x + 4168

X = 3000

Therefore, viswasam invested Rs.3000 In bank B.

Let the number of years invested by Sarkar and viswasam be x years and y years respectively.

3000 × (30 / 100) × y – 1800 × (25 / 100) × x = 1800

900y – 450 x = 1800—- (i)

X+ y = 5 —–(ii)

On solving above two equations, we get

X = 2 and y = 3

Required years = 3


DAY 6 Questions

Q.1) A tank is fitted with 12 pipes. Some of them are inlet and some of them are outlet. Each inlet pipe can fill the tank in 10 hours and each outlet pipe can empty the tank in 8 hours. If all the pipes are opened together the tank will be filled in  hours. The number of outlet pipes is numerically equal to the number of years invested by a person in a bank. The amount which he invested is Rs.29120 and the rate of interest is 20% @ C.I. The interest amount he received from the bank is numerically equal to the area of a square. The perimeter of the square is numerically equal to the value of x.  

720%  of  780 + 820 % of 150-51² – x = y + 2.6. Find the value of y.

a) 3620

b) 3640

c) 3450

d) 3660

e) 3560


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Q.1) d

Let take number of inlet pipes = x

Number of outlet pipes = 12-x

 

X= 9

Number of inlet pipes = 9

Outlet pipes = 3

Therefore, number of years invested = 3 years

Compound interest =P (1+(R/100)) ³– P

=29120 (120/100)³ – 29120

=21199.36

Area of square = 21199.36

a² = 145.6

Perimeter = 4a=4×145.6=582.4m

5616+ 1230 – 2601- 582.4 = y +2.6

3660= y


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Questions of DAY 11 UPDATED now. Answer for the BLUE WHALE CHALLENGE now and mention the Answers in the Comments. 


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