# Crack IBPS PO : Time and Work – Day 2

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IBPS PO Prelims is scheduled to be starting at Oct 7. As you know the difficulty level increases with every exam, we have made sure the questions asked in these days of daily test entices you to do more questions other than this. This course extends to 100 days and the questions ranges from easy to moderate to extremely difficult. We will provide solutions for the questions asked with detailed description, Since many of you will have doubts regrading some questions.

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## IBPS PO Time and Work

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**IBPS PO Study Planner**

IBPS PO Time and Work Day – 2

No.of Questions: 10

Time : 10 mints

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- Question 1 of 10
##### 1. Question

1 pointsCategory: AptitudeSunil can do a work in 36 days, Ram in 54 days and Balu in 72 days. They started working together but, before the work was to be over, Sunil left 8 days before and 12 days before Ram. Balu will complete the work alone in

Correctb

Let x be the number of days in which Balu alone can finish the work at the end.

(x- 8)/36+ (x-12)/54+ x/72=1

X = 24 daysIncorrectb

Let x be the number of days in which Balu alone can finish the work at the end.

(x- 8)/36+ (x-12)/54+ x/72=1

X = 24 days - Question 2 of 10
##### 2. Question

1 pointsCategory: AptitudePacino ,Crowe and Natalie are three people who can complete a work in 25, 10 and 20 days respectively. What is the minimum number of days required to complete the work If not more than 2 people among them work on the same day and no 2 consecutive days have the same pair of people working?

Correctc

Efficiency of Pacino = 4 %

Efficiency of Crowe = 10 %

Efficiency of Natalie = 5 %

So, Pacino + Crowe = 14%, Crowe + Natalie = 15% and Pacino + Natalie = 9%

To reduce the number of days we have to select the pair with more efficiency.

So, If we select Pacino + Crowe and Crowe + Natalie alternatively We will get our value

So, 15+14+15+14+15+14 = 87% work is done in 6 days.

So, the remaining 13% can be done in 13/15 days.

So, minimum number of days required is 6+ 13/15=103/15 daysIncorrectc

Efficiency of Pacino = 4 %

Efficiency of Crowe = 10 %

Efficiency of Natalie = 5 %

So, Pacino + Crowe = 14%, Crowe + Natalie = 15% and Pacino + Natalie = 9%

To reduce the number of days we have to select the pair with more efficiency.

So, If we select Pacino + Crowe and Crowe + Natalie alternatively We will get our value

So, 15+14+15+14+15+14 = 87% work is done in 6 days.

So, the remaining 13% can be done in 13/15 days.

So, minimum number of days required is 6+ 13/15=103/15 days - Question 3 of 10
##### 3. Question

1 pointsCategory: AptitudeA can do a work in 24 days and B in 30 days. If they work on it together for 4 days, then the fraction of the work that is left is

CorrectC

A’s 1 day work = 1/24

B’s 1 day work = 1/30

A+B 1 day work = 1/24 + 1/30= 3/40

A+B’s 4 day work = 3/40 × 4 = 3/10

Remaining work = 1- 3/10 = 7/10IncorrectC

A’s 1 day work = 1/24

B’s 1 day work = 1/30

A+B 1 day work = 1/24 + 1/30= 3/40

A+B’s 4 day work = 3/40 × 4 = 3/10

Remaining work = 1- 3/10 = 7/10 - Question 4 of 10
##### 4. Question

1 pointsCategory: AptitudeRamesh can do a maths assessment consisting of 100 questions alone in 5 hours. Ramesh’s friends Surbhi and Alaka together can do the same set of questions in 1/3 speed of Ramesh. Pintu and Deepak together can do the same set of questions at 1/5 speed of Ramesh. If the five of them do the set of questions together, In how much time can they complete 368 set of questions?

Correctd

Number of questions done by Ramesh in 1 hour = 100/5=20

Number of questions done by Surbhi and Alaka in 1 hour = (20×1)/3=20/3

Number of questions done by Pintu and Deepak in 1 hour = 20/5=4

In one hour , they can do 20+ 20/3+4=92/3 questions.

So they can do, 368 set of questions in(368/92)×3 = 12 hour .Incorrectd

Number of questions done by Ramesh in 1 hour = 100/5=20

Number of questions done by Surbhi and Alaka in 1 hour = (20×1)/3=20/3

Number of questions done by Pintu and Deepak in 1 hour = 20/5=4

In one hour , they can do 20+ 20/3+4=92/3 questions.

So they can do, 368 set of questions in(368/92)×3 = 12 hour . - Question 5 of 10
##### 5. Question

1 pointsCategory: AptitudeKolan can complete a work in 25 days and Renu can complete a work in 30 days. Both of them start the work together and then Solan joins them after some days and the whole work is done in 9 days. After that they are paid a sum of Rs.1500. What is the share of Solan?

Correcte

Let us assure they do 100 units of work.

Efficiency of Renu=100/30=10/3%

Efficiency of Kolan=100/25=4%

Total efficiency =4+ 10/3=22/3%

Now as both of them work for all the 9 days then the percentage of work done by them would be =9× 22/3=66%

The amount of work that is left to be done is = 100-66 = 34%

This 34% work is done by solan.

So, Share of solan in the amount of Rs.1500 =34/100×1500=Rs.510Incorrecte

Let us assure they do 100 units of work.

Efficiency of Renu=100/30=10/3%

Efficiency of Kolan=100/25=4%

Total efficiency =4+ 10/3=22/3%

Now as both of them work for all the 9 days then the percentage of work done by them would be =9× 22/3=66%

The amount of work that is left to be done is = 100-66 = 34%

This 34% work is done by solan.

So, Share of solan in the amount of Rs.1500 =34/100×1500=Rs.510 - Question 6 of 10
##### 6. Question

1 pointsCategory: AptitudeA tank has two inlet pipes which can fill the empty tank in 10 hours and 20 hours working alone and one outlet pipe which can empty the full tank in 8 hours working alone. The inlet pipes are kept open for all the time but the outlet pipe was opened after 2 hours for one hour and then again closed for 2 hours then once again opened for one hour. This pattern of outlet pipes continued till the tank get completely filled. In how many hours the tank has been filled, working on the given pattern?

Correctc

Efficiency of two inlet pipes A and B = 100/10%+100/20%=15%

Efficiency of the outlet pipe C = 100/8=12.5%

Now, Efficiency of two inlet pipes A and B along with an outlet pipe C

= 15%-12.5% = 2.5%

Tank filled in 3 hours = (15+ 15+ 2.5) = 32.5%

So, tank filled in 9 hours = (3×32.5) = 97.5%

Remaining = (100-97.5)% = 2.5%

On the 10th hour 2.5% will be filled by pipe A, B with its 15% efficiency.

Time taken = 2.5/15=1/6 hours = 10 minutes.

Total time = 9 hours and 10 minutesIncorrectc

Efficiency of two inlet pipes A and B = 100/10%+100/20%=15%

Efficiency of the outlet pipe C = 100/8=12.5%

Now, Efficiency of two inlet pipes A and B along with an outlet pipe C

= 15%-12.5% = 2.5%

Tank filled in 3 hours = (15+ 15+ 2.5) = 32.5%

So, tank filled in 9 hours = (3×32.5) = 97.5%

Remaining = (100-97.5)% = 2.5%

On the 10th hour 2.5% will be filled by pipe A, B with its 15% efficiency.

Time taken = 2.5/15=1/6 hours = 10 minutes.

Total time = 9 hours and 10 minutes - Question 7 of 10
##### 7. Question

1 pointsCategory: AptitudeRoy and Paul are two workers, working together they can complete the Whole work in 15 hours. If the Roy worked for 2.5 hours and , Paul worked for 2.5 hours. Still there was half of the work to be done .If Roy is working alone, then how much percent of the work is done by Roy in six hours?

Correcte

According to the question,

2.5/Roy+2.5/paul+6/paul=1/2

2.5(1/Roy+1/Paul)+6/Paul=1/2

2.5/15+6/Paul=1/2

6/paul=1/2-1/6=2/6=1/3

Paul = 18 hours

1/Roy=1/15-1/18=1/90

Roy can complete the work in 90 hours

Work done by Roy in one hour = 1/90

Work done by Roy in six hours = 1/15

Required percentage = 1/15×100=6.67%Incorrecte

According to the question,

2.5/Roy+2.5/paul+6/paul=1/2

2.5(1/Roy+1/Paul)+6/Paul=1/2

2.5/15+6/Paul=1/2

6/paul=1/2-1/6=2/6=1/3

Paul = 18 hours

1/Roy=1/15-1/18=1/90

Roy can complete the work in 90 hours

Work done by Roy in one hour = 1/90

Work done by Roy in six hours = 1/15

Required percentage = 1/15×100=6.67% - Question 8 of 10
##### 8. Question

1 pointsCategory: AptitudeA tank can be filled by two pipes P and Q in 18 minutes and 27 minutes respectively, If only one pipe is opened at one time. If both the pipes are opened simultaneously, after how much time should pipe P be closed so that the unfilled part of the tank is filled in by pipe Q in 15 minutes?

CorrectNone of these

Answer : 4.8 Min

IncorrectNone of these

Answer : 4.8 Min

- Question 9 of 10
##### 9. Question

1 pointsCategory: AptitudeA, B and C working together can complete a work in 4/3 hours. If A works at half his speed and C works at twice his speed, the time taken to complete the work (all three still working together) remains same. If B decreases his speed by 50%, the time taken by B to complete the work becomes equal to time taken by C. Find the time taken (in hours) to complete the work if only A and C work together?

Correcta

Let the time taken by A alone to complete the work = a hours, for B it is b hours, and for C, it is c hours.

1/(1/a+1/b+1/c)=4/3——(1)

From the First statement, time taken by A = half of time taken by C.

Hence c = 2a.

From the second statement, 1.5b = c.

Hence, b = 2a/1.5

Solving these equations——(1), a = 3 hours, b= 4 hours and c= 6 hours.

Time taken by A and C working together = 1/(1/3+1/6) = 2 hoursIncorrecta

Let the time taken by A alone to complete the work = a hours, for B it is b hours, and for C, it is c hours.

1/(1/a+1/b+1/c)=4/3——(1)

From the First statement, time taken by A = half of time taken by C.

Hence c = 2a.

From the second statement, 1.5b = c.

Hence, b = 2a/1.5

Solving these equations——(1), a = 3 hours, b= 4 hours and c= 6 hours.

Time taken by A and C working together = 1/(1/3+1/6) = 2 hours - Question 10 of 10
##### 10. Question

1 pointsCategory: AptitudeAjith and Vijay can do 13/17 of the work together and Vijay and Dhanush can do 7/17 of the work together. If three of them are paid a total of Rs. 629 for their work then what is the amount that Ajith is paid for his work?

Correctc

Let the amount paid to ajith, vijay and dhanush be a, b and c respectively.

So, a+b=13/17×629=Rs.481.

And b+c=7/17×629=Rs.259

a+b+c=629

a=629-259=370;

Q.111) a

P’s 1 day’s work = 1/8

Q’s 1 day’s work = 1/12

R’s one day’s work = 1/24

Let the number of days taken be x

Then,

x/6+(x-1)/12+(x-2)/24=1

7x-4 = 24

x = 4 days.Incorrectc

Let the amount paid to ajith, vijay and dhanush be a, b and c respectively.

So, a+b=13/17×629=Rs.481.

And b+c=7/17×629=Rs.259

a+b+c=629

a=629-259=370;

Q.111) a

P’s 1 day’s work = 1/8

Q’s 1 day’s work = 1/12

R’s one day’s work = 1/24

Let the number of days taken be x

Then,

x/6+(x-1)/12+(x-2)/24=1

7x-4 = 24

x = 4 days.

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## 2 comments

You guys sure about the answers? The 8th one seems wrong. And the questions lack clarity. Pardon if itz my mistake…

Tricky… Wavoo!!

Comments are closed.