# Dare To Solve Day 1

Dear Bankersdaily Aspirants,

Amar, Vasanth and Jai are three workers, employed by a contractor. They completed the whole work in 10 days. Initially all of them worked together, but the last 60%of the work was completed by only Vasanth and Jai together. Amar worked with Vasanth and Jai only for initial two days then he left the work due to his poo health. Also Vasanth takes 20% less time to finish the work alone than that of Jai working alone. If they were paid Rs. 3000 for the entire work, then what is the share of least efficient person?

Explanation:

Given:

 Total Working Piece Number of Days Number of Persons Efficiency 1000 Pieces 10 days 3 persons 100 60 % Work 600 Pieces 8 days 2 Persons 75 40 %  of Work 400 Pieces 2 days 3 Persons 200

From above it is clear that the Efficiency of Amar is  125=(200-75)

Given that Vasanth takes 20% less time than Jai,

Therefore

TIME:

If Jai takes X days,Vasanth takes (4/5)X days

EFFICIENCY:

Efficiency is Inversely Proportional   to Time.

Jai’s Efficiency is X and Vasanth’s Efficiency is  (5/4)X

X +(5/4 )X=75

(4X+5X)/4=75

9X=75 × 4

X=(75 × 4)/9

X=33.33%

Vasanth’s Efficiency = =41.6%

Jai is Least Efficient=33.33%

Therefore Share of Jai is=RS.1000